All categories

3 years ago

Please help! I'm so confused!

Mathematics

1 answer:

sergejj [24]3 years ago

4 0

I think it’s saying like is it a parallel or so

You might be interested in

Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

7 0

3 years ago

Given<br> f(x) = -4(x+5),<br> what is the value of<br> f(-3)?<br>

sp2606 [1]

Answer:

f(-3)=-8

Step-by-step explanation:

plug -3 in as x

-4(-3+5)

12-20

-8

4 0

2 years ago

Find all solutions in the interval [0, 2π). tan x + sec x = 1

svp [43]

Use the identity
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x = 1 + tan^2x - 2 tan x
0 = -2 tanx

tan x = 0

x = 0, π
π is an extraneous root because sec 180 = -1
So the answer is 0 degrees

6 0

3 years ago

Bob has some 10 ltb weights and some 3 lb weights. Together, all his weights add up to 50 lbs. If x represents the number of 3 l

____ [38]

total weight = 50

3x + 10y = 50

7 0

3 years ago

A jar contains $14.25 in quarters and dimes. There are 75 coins in the jar. Find the number of quarters in the jar.

Marianna [84]

Set up a system of equations.
d + q = 75
.1d + .25q = 14.25

Multiply the first equation by -.1 so that the "d's" will cancel.
-.1d -.1q = -7.5
.1d +.25q = 14.25
Now add the two equations together
.15q = 6.75
divide both sides by .15
q = 45
There are 45 quarters in the jar

8 0

3 years ago