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weqwewe [10]
3 years ago
5

Joe's done expressed earned 4378 Audi festival by selling chocolate or vanilla donuts for two dollars each if they sold 978 choc

olate donuts how many bundle donuts did they seJoe's done expressed earned 4378 Audi festival by selling chocolate or vanilla donuts for two dollars each if they sold 978 chocolate donuts how many vanilladonuts did they sell
Mathematics
1 answer:
Bad White [126]3 years ago
8 0

Answer:

Joe's done expressed sold 1211 Vanilla donuts.

Step-by-step explanation:

Given:

Total Money earned = 4378

Number of chocolate donuts sold = 978

Cost of each donuts = 2 dollars

We need to find the number of vanilla donuts sold.

Solution:

Let number of vanilla donuts sold be 'x'.

now we can say that;

Total Money earned is equal to sum of Number of chocolate donuts sold and number of vanilla donuts sold multiplied by Cost of each donuts.

framing in equation form we get;

2(x+978)=4378\\\\2x +2\times 978 =4378\\\\2x+1956=4378

Subtracting both side by 1956 we get;

2x-+1956-1956=4378-1956\\\\2x= 2422

Dividing both side by 2 we get;

\frac{2x}{2}=\frac{2422}{2}\\\\x = 1211

Hence Joe's done expressed sold 1211 Vanilla donuts.

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F(x)=2x+1; g(x)=3x-2 <br><br> find (f+g) (3)
baherus [9]

Step-by-step explanation:

GIVEN,

f(x)=2x+1; g(x)=3x-2

NOW,

( 2x+1 + 3x-2)×3

=(5x-2)×3

=15x - 6 <em>A</em><em>N</em><em>S</em><em>W</em><em>E</em><em>R</em>

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3 years ago
A rectangular storage container with an open top is to have a volume of 24 cubic meters. The length of its base is twice the wid
Mariana [72]

Answer:

419.25

Step-by-step explanation:

The calculation of the cost of materials for the cheapest such container is shown below:-

We assume

Width = x

Length = 2x

Height = h

where, length = 2 \times width

Base area = lb

= 2x^2

Side area = 2lh + 2bh

= 2(2x)h + 2(x)h

= 4xh + 2xh

Volume = 24 which is lbh = 24

h = \frac{24}{2x^2} \\\\ h = \frac{12}{x^2}

Now, cost is

= 13(2x^2) + 9(4xh + 2xh)\\\\ = 13(2x^2) + 9(4x + 2x)\times \frac{12}{x^2} \\\\ = 26x^2 + \frac{648}{x}

now we have to minimize C(x)

So, we need to compute the C'(x)

= 52x - \frac{648}{x^2}

C"(x)  = 52x - \frac{1,296}{x^3}

now for the critical points, we will solve the equation C'(x) = 0

= 52x - \frac{648}{x^2} = 0\\\\ x = \frac{648}{52}^{\frac{1}{3}}

C" = ((\frac{648}{52} ^{\frac{1}{3} } = 52 + \frac{1296}{(\frac{648}{52})^\frac{1}{3} )^3}\\\\ = 52 + \frac{1296}{\frac{648}{52} } >0

So, x is a point of minima that is

= (\frac{648}{52} )^\frac{1}{3}

Now, Base material cost is

= 13(2x^2)\\\\ = 26(\frac{648}{52} )^\frac{2}{3}

= 139.75

Side material cost is

= \frac{648}{x} \\\\ = \frac{648}{(\frac{648}{52})^\frac{1}{3}  }

= 279.50

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Total cost is

= 139.75 + 279.50

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Answer:

Step-by-step explanation:

To solve this problem you need the function

 

h(t) = -16t2 + v0t + h0

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And we can solve for t

 

If we rearrange the terms we see that this is a difference of 2 squares

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The second solution is discarded as time cannot be negative.

 

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Answer:

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