Winter pemmican, berry pemmican and dried buffalo meat are some of the food products made from buffalo that fed the Native Americans through the winter.
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Explanation:</u></h3>
Native Americans were mostly into agricultural activities. Through out the winters, they would feed on the supply they had grown and stored. Irrespective of their agricultural activities, they were heavy meat-eaters. They ate meat of deer, buffalo, elk, turkeys and other kinds of birds, some sea food which would also include whales at times.
Buffaloes were one of the most important resource for the Native Americans. The animal was a source for food, clothing, weapons and tools. As for the food supply in winters, the people stored and preserved various body parts of the buffalo in parfleches, also known as hide containers.
Rickie knows that Angela Merkle is the name of a chancellor of Germany. Rickie is retrieving this information from storage in sematic memory.
This is called the critical period.
The critical period itself is a stage of the development in the life of a human being in which is said that skills are most easily and most readily learned and acquired. This period usually varies for different things like binocular vision and language, but it is said that after the critical period the skills are acquired with much difficulty if they are to be acquired at all.
Answer: An organization of Southeast Asian nations that promote regional unity
Explanation: ASEAN - The Association of South East Nations - 10-member group
Allele frequency is used to display the genetic diversity of a species population .
Explanation:
To calculate the frequency of the recessive allele we use the
THardy-Weinberg equation
p² + 2pq + q²
p+q=1
p is the frequency of the homozygous dominant genotype
q is the frequency of the homozygous recessive genotype
2pq is the frequency of the heterozygous genotype.
Total number of individuals = 45 + 30+ 25 = 100
So, the frequency of recessive trait = 25/100 =0.25.
Thus, the value of q² = 0.25
So, q would be equal to square root of 0.25 which comes out to be 0.5