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2 years ago

(ii) n is an integer and 6n +5 <20

Mathematics

1 answer:

Sonja [21]2 years ago

3 0

6n + 5 < 20

Subtract both sides 5

6n + 5 - 5 < 20 - 5

6n < 15

Divide both sides by 6

6n ÷ 6 < 15 ÷ 6

n < 15/6

n < 3×5/3×2

n < 5/2

n < 2.5

n《 2

Thus the largest value of n is :

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My math final please help

spin [16.1K]

Answer:

m∠3 = 56

Step-by-step explanation:

Let's solve for x, first:

x + 9 = 3x - 85

9 = 2x - 85

94 = 2x

94/2 = x

47 = x

Now that we have x-value, we can substitute it in any one of the given equation to find angle 3 since, angle 1, 7 and 3 all are congruent:

=> m∠7 = x + 9

=> m∠7 = 47 + 9

=> m∠7 = 56

Since m∠7 ≅ m∠3

and m∠7 = 56, then

Hope this helps!

6 0

2 years ago

Jaime has 8/10 of a candy bar left over. He wants to split it into 1/3 pieces.

Valentin [98]

Answer:

2 pieces.

Step-by-step explanation:

To identify how many pieces he can split with 8/10 of a candy bar, divide 8/10 by 1/3.

<u>Divide 8/10 by 1/3:</u>

$\frac{8}{10} / \frac{1}{3}=$

<u>Find the Ricipricol, then flip the sign:</u>

$\frac{8}{10} (\frac{3}{1} )=$

<u>Multiply:</u>

<u /> $\frac{8}{10} (\frac{3}{1})=\frac{24}{10} =\frac{2.4}{1}$

2.4 represents how many pieces of chocolate he can make with 8/10 of a candy bar.

However, 2.4 pieces can't be made, therefore he can only make 2 <u>full</u> pieces.

6 0

2 years ago

Yuan has 5 quarts of broth. He uses 1/2 of the broth to make soup. Then, he uses 1/4 of the broth he has left to make gravy.

vovangra [49]

Answer:

1 7/8 quarts

Step-by-step explanation:

The amount Yuan has left can be found by multiplying the original amount by the fraction he has left.

After using 1/2 of the broth for soup, the fraction remaining is ...

1 -1/2 = 1/2

The amount Yuan used for gravy is 1/4 of this, or ...

(1/4)(1/2) = 1/8 . . . of the original amount of broth

The total fraction Yuan used was ...

fraction used = fraction for soup + fraction for broth = 1/2 +1/8 = 5/8

<h3>remaining</h3>

Then the fraction remaining is ...

fraction remaining = 1 - fraction used = 1 - 5/8 = 3/8.

The amount remaining is this fraction of the original amount:

(3/8)(5 quarts) = 15/8 quarts = 1 7/8 quarts . . . . remaining

7 0

2 years ago

Anyone know the answer to this algebra problem?

ikadub [295]

Answer: $\bold{a=1\qquad b=\dfrac{1}{16}\qquad c=\dfrac{1}{64}\qquad d=1\qquad e=\dfrac{4}{9}\qquad f=\dfrac{16}{81}}$

<u>Step-by-step explanation:</u>

$\begin{array}{c|l}\underline{\quad x\quad}&\underline{\quad 4^{-x}\qquad \qquad}\\-1&4^{-(-1)}=4^1=4\\\\0&4^{-(0)}=4^0=1\\\\2&4^{-(2)}=\dfrac{1}{4^2}=\dfrac{1}{16}\\\\4&4^{-(4)}=\dfrac{1}{4^4}=\dfrac{1}{64}\end{array}$

$\begin{array}{c|l}\underline{\quad \bigg x \quad}&\underline{\quad \bigg(\dfrac{2}{3}\bigg)^x\qquad \qquad}\\\\-1&\bigg(\dfrac{2}{3}\bigg)^{-1}=\dfrac{3}{2}\\\\0&\bigg(\dfrac{2}{3}\bigg)^{0}=1\\\\2&\bigg(\dfrac{2}{3}\bigg)^{2}=\dfrac{2^2}{3^2}=\dfrac{4}{9}\\\\4&\bigg(\dfrac{2}{3}\bigg)^{4}=\dfrac{2^4}{3^4}=\dfrac{16}{81}\end{array}$

3 0

3 years ago

How do I find the answer for this equation 20x+15y= 330, when x+y =18

Maru [420]

U divide 330 by 15 and get the quotient then do the same thing to 20 and add the quotients together to solve for x and y

6 0

3 years ago