Ayita made 5 1/2 cups of trail mix. She want to divide the trail mix into 3/4 cup servings.How many servings will she have?

Form a quadratic polynomial whose zeroes are 3-√3/5 and 3+√3/5?

barxatty [35]

Answer:

x^2 -6x + 222/25

Step-by-step explanation:

If the zeros are as above, then ;

x = 3-√3/5 or x = 3 + √3/5

Firstly, let’s represent √3/5 by b

Thus;

The two roots are ;

x = 3-b or x = 3 + b

so;

x+ b -3 and x -3-b

The quadratic equation is the product of the two

(x + b-3)(x - b -3)

x(x - b-3) + b(x -b -3) -3(x - b -3)

= x^2 -bx -3x + bx -b^2 -3b -3x + 3b + 9

Collect like terms and we are left with;

x^2 -6x -b^2 + 9

So let’s put back b = √3/5

x^2 -6x -(√3/5)^2 + 9

x^2 -6x -3/25 + 9

x^2 -6x + 222/25

3 0

3 years ago

Molly wants to pursue a graduate degree at New University but is unsure whether to specialize in law or medicine. To help her de

Mashutka [201]

Answer:

Molly's Z score for LSAT

z-score=-2

Molly's Z score for MCAT

z-score=2

Step-by-step explanation:

z-score for LSAT

Molly's score=120

mean=150

Standard deviation=15

z-score= (Molly LSAT score-mean)/standard deviation

z=120-150/15=-30/15=-2

z-score for MCAT

Molly's score=52

mean=40

Standard deviation=6

z-score= (Molly MCAT score-mean)/standard deviation

z=52-40/6=12/6=2

3 0

2 years ago

Let f(x)= x(2x-3)/(x+2)x. Find the domain, vertical and horizontal asymptote

Reptile [31]

Step-by-step explanation:

Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues

Here, we have

$\frac{x(2x - 3)}{(x + 2)x}$

First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.

Since, we don't want x to be 0,

We have a removable discontinuity at x=0

Now, we have

$\frac{2x - 3}{x + 2}$

We don't want the denomiator be zero because we can't divide by zero.

so

$x + 2 = 0$

$x = - 2$

So our domain is

All Real Numbers except-2 and 0.

The vertical asymptors is x=-2.

To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of

The leading coeffixent of the numerator/ the leading coefficent of the denomiator.

So that becomes

$\frac{2}{1} = 2$

So we have a horinzontal asymptofe of 2

7 0

2 years ago

If p(x) = x^2 + 7x + 3 is divided by x + 4, the remainder is <br> a0

Sphinxa [80]

Hope this helps you!

4 0

3 years ago

You have also set up a card game in which a player picks a card from a standard deck of 52 cards. The player wins if these two e

Alenkinab [10]

First, let's count:

there are 26 possible outcomes for E1 (black card)

there are 4x9 = 36 possible outcomes for E2, to pick a numbered card (any color)

there are 2x9 =18 possible outcomes for E1 (black) AND E2 (numbered, spade + clower)

the probability of E1 AND E2 is the ratio of the count of possible outcomes for E1 + E2 and the count of all possible outcomes (52 choices to pick a card from the deck):

P(E1 and E2) = 18/52 (34.6%)

And as asked:

P(E1) = 26/52 = 1/2 (50%)

P(E2) = 36/52 = 9/13 (69.2%)

5 0

2 years ago