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3 years ago

C(ge + p) = n +j Solve for c: C=

Mathematics

1 answer:

REY [17]3 years ago

4 0

Answer:

$c(ge + p) = n + j \\ \\ \frac{c(ge + p)}{(ge + p)} = \frac{n + j}{(ge + p)} \\ \\ { \boxed{ \boxed{c = \frac{n + j}{ge + p} }}}$

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What is 87 24 over 25 as a decimal

erastova [34]

8724/25 = 348.96
When you say "over" that means that it has to be divided that short subtraction sign that separates the numerator and the denominator and also means divide so I believe that if you divide you can find the decimal.

7 0

3 years ago

Mathematical Statistics with Applications Help Homework

Mars2501 [29]

7.43: Let $X$ denote the random variable for height and $\overline X$ for the sample mean. Then if $\mu$ is the mean of

So the probability that the difference between the sample and population means does not exceed 0.5 inch is

$P(|\overline X-\mu|\le0.5) = P\left(\left|\dfrac{\overline X-\mu}{0.25}\right|\le\dfrac{0.5}{0.25}\right) = P(|Z|\le 2) \approx \boxed{0.95}$

per the empirical or 68/95/99.7 rule.

7.44: For a sample of size n, the sample standard deviation would be $\frac{2.5}{\sqrt n}$ . We want to find n such that

$P(|\overline X-\mu| < 0.4) = 0.95$

Comparing to the equation from the previous part, this means we would need

$\dfrac{0.4}{\frac{2.5}{\sqrt{n}}} = 0.16\sqrt n = 2 \implies \sqrt n = 12.5 \implies n = 156.25$

so a sample of at least 157 men would be sufficient.

7 0

3 years ago

Use the following image to assist in your answer. a = - 6 - 9 - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

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3 years ago

A bag contains 5 quarters 2 dimes and 4 pennies what is probability Of picking a dime

Snezhnost [94]

Answer:

2/11 or 18 %

Step-by-step explanation:

4 0

3 years ago

ਇਕ ਐਕਸੈਲ ਵਰਕਬੁੱਕ ਵਿੱਚ ਹੁੰਦੀਆ ਹਨ

kompoz [17]

Answer:

Cannot understand, please translate

Step-by-step explanation:

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3 years ago

C(ge + p) = n +j Solve for c: C=​

C(ge + p) = n +j Solve for c: C=