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svlad2 [7]
3 years ago
12

A box contains 1 plain pencil and 4 pens. A second box contains 6 color pencils and 2 crayons. One item from each box is chosen

at random. What is the probability that a pen from the first box and a crayon from the second box are selected?
Mathematics
1 answer:
FrozenT [24]3 years ago
8 0

Probability that a pen from the first box and a crayon from the second box are selected is 1/5.

<u>Step-by-step explanation</u>:

Step 1 :

  • First box contain = 1 pencil + 4 pens = 5 items
  • Second box contain = 6 color pencils + 2 crayons = 8 items

Step 2 :

Probability for a pen from 1st box, P(pen) = no. of pens / total items

P(pen) = 4/5

Probability for a crayon from 2nd box, P(crayon) = no. of crayons / total items

P(crayon) = 2/8 = 1/4

Step 3 :

P(pen) and P(crayon) = (4/5) \times (1/4)

                                   = 4/20

P(pen) and P(crayon) = 1/5

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See Below.

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Statements:                                              Reasons:

1)\, XY=XZ                                              Given

2) \text{ $ m\angle Y= m\angle Z$}                                        Isosceles Triangle Theorem

\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}                  Angle Addition

\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}                               Given

5) \text{ $m\angle XYQ=m\angle QYZ$}                           Definition of Bisector

\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}                               Substitution

7)\text{ $m\angle Z=m\angle XZP+m\angle PZY$}              Angle Addition

8)\text{ $ZP$ bisects $\angle XZY$}                              Given

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