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Svetllana [295]
4 years ago
8

The alpha particles leave visible tracks in the cloud chamber because

Physics
1 answer:
julia-pushkina [17]4 years ago
6 0
<h2>Answer: Ionization </h2>

The inner atmosphere of a <u>cloud chamber</u> is composed of an easily ionizable gas, this means that little energy is required to extract an electron from an atom. <u>This gas is maintained in the supercooling state, so that a minimum disturbance is enough to condense it</u> in the same way as the water is frozen.

<h2>Then, when a charged particle with enough energy interacts with this gas, it <u>ionizes</u> it. </h2>

This is how alpha particles are able to ionize some atoms of the gas contained inside the chamber when they cross the cloud chamber.

These ionized atoms increase the surface tension of the gas around it allowing it to immediately congregate and condense, making it easily distinguishable inside the chamber like a <u>small cloud</u>. In this way, it is perfectly observable the path the individual particles have traveled, simply by observing the cloud traces left in the condensed gas.

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White objects absorb all wavelengths of light? true or false
IRISSAK [1]
White objects do not absorb all wavelenghts. The statement is false
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3 years ago
The velocity of a ball as it is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds. What is the average a
Step2247 [10]

Change in speed = (speed at the end) minus (speed at the beginning)

                           =                    (0 - 20 m/s)  =  -20 m/s

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                           =  (-20 m/s)      /   (3.5 sec)   =   -5.71 m/s²

Notice that this story probably didn't happen on Earth, because
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3 years ago
A mule is harnessed to a sled having a mass of 246 kg, including supplies. The mule must exert a force exceeding 1210 N at an an
zimovet [89]

(a) 1800 N

The equation of the forces along the vertical direction is:

F sin \theta + N - mg = 0

where

F sin \theta is the component of the applied force along the vertical direction

N is the normal force on the sled

mg is the weight of the sled

Substituting:

F = 1210 N

m = 246 kg

\theta = 30.3^{\circ}

We find N:

N=mg-F sin \theta = (246)(9.8)-(1210)(sin 30.3^{\circ})=1800 N

(b) 0.580

The equation of the forces along the horizontal direction is:

F cos \theta - \mu_s N = 0

where

F cos \theta is the horizontal component of the push applied by the mule

\mu_s N is the static frictional force

Substituting:

F = 1210 N

N = 1800 N

\theta = 30.3^{\circ}

We find \mu_s, the coefficient of static friction:

\mu_s = \frac{F cos \theta}{N}=\frac{(1210)(cos 30.3^{\circ})}{1800}=0.580

(c) 522 N

In this case, the force exerted by the mule is

F= 6.05 \cdot 10^2 N = 605 N

So now the equation of the forces along the horizontal direction can be written as

F cos \theta - F_f = 0

where

\theta=30.3^{\circ}

and F_f is the new frictional force, which is different from part (b) (because the value of the force of friction ranges from zero to the maximum value \mu N, depending on how much force is applied in the opposite direction)

Solving the equation,

F_f = F cos \theta = (605)(cos 30.3^{\circ})=522 N

6 0
3 years ago
Which part of the earth do the suns direct rays hit during the summer solstice
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December 21 is the "Summer" solstice in the Southern hemisphere.
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8 0
3 years ago
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Net Force = 600 N
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