Assuming the raindrop was stationary relative to the vertical distance to the ground at the start:
D=0.5at where d is distance, a is acceleration and t is time
D is 300 meters
a is 9.8 meter/sec squared
Solve for t in seconds
t = 61.2 seconds
v=at where v is velocity
a is 9.8 meters per second squared
t is 61.2 seconds
solve for v
v = 600 meters per second.
If it had an initial vertical velocity (v0) at the start :
d= 0.5at+v0t
and
v=at+v0
The electric potential at the origin of the xy coordinate system is negative infinity
<h3>What is the electric field due to the 4.0 μC charge?</h3>
The electric field due to the 4.0 μC charge is E = kq/r² where
- k = electric constant = 9.0 × 10 Nm²/C²,
- q = 4.0 μC = 4.0 × 10 C and
- r = distance of charge from origin = x₁ - 0 = 2.0 m - 0 m = 2.0 m
<h3>What is the electric field due to the -4.0 μC charge?</h3>
The electric field due to the -4.0 μC charge is E = kq'/r² where
- k = electric constant = 9.0 × 10 Nm²/C²,
- q' = -4.0 μC = -4.0 × 10 C and
- r = distance of charge from origin = 0 - x₂ = 0 - (-2.0 m) = 0 m + 2.0 m = 2.0 m
Since both electric fields are equal in magnitude and directed along the negative x-axis, the net electric field at the origin is
E" = E + E'
= -2E
= -2kq/r²
<h3>What is the electric potential at the origin?</h3>
So, the electric potential at the origin is V = -∫₂⁰E".dr
= -∫₂⁰-2kq/r².dr
Since E and dr = dx are parallel and r = x, we have
= -∫₂⁰-2kqdxcos0/x²
= 2kq∫₂⁰dx/x²
= 2kq[-1/x]₂⁰
= -2kq[1/x]₂⁰
= -2kq[1/0 - 1/2]
= -2kq[∞ - 1/2]
= -2kq[∞]
= -∞
So, the electric potential at the origin of the xy coordinate system is negative infinity
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<span><span>A 0.200 kg plastic ball moves with a velocity of0.30 m</span>s<span>A 0.205-kg plastic ball moves with a velocity of0.30 m</span><span>A 0.199 kg plastic ball moves with a velocity of0.30 m</span><span>A 0.204-kg plastic ball moves with a velocity of0.30 m</span><span>A 100 g ball moving to the right at 4.0 m</span>s collides<span>have less momentum if the velocities</span><span>the same</span><span>A ball with a momentum of 4.0 kg•<span>m</span></span></span>
D. The block should move to the left.
Since the forces are in opposite directions the difference of these forces determines the magnitude and direction of the block. Therefore,
20 N left - 10 N right = 10 N left