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3 years ago

This is a textbook question, work too please!

Physics

1 answer:

lara [203]3 years ago

4 0

The force is not pulling in the direction that the box is moving.
Only the force in the horizontal direction does work.
The force in the vertical direction doesn't do any work, because
   the box doesn't move through any vertical distance.

The horizontal force is 200(cos 45°) = 142 newtons

The vertical force is 200(sin 45°) = 142 newtons

If you pull the box 5 meters, then the amount of work done is

   (force) x (distance) = (142 N) x (5 m) = 710 joules.

Power = (work done) / (time to do the work)

   = (710 joules) / (5 seconds) = 142 watts .

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What statement best describes his motion as he jogs around the curved part of the track?

-BARSIC- [3]

Answer:

The answer would be A.

Explanation:

5 0

3 years ago

Hey pls help thanks a lot

galben [10]

Answer:

I am not sure about the answer as I don't have a proper calculator besides me now

Explanation:

but I used this equation:

(8.20)sin30(1-d)=10d

Idk whether it is correct or not, I'm just a student too

what is your method of doing this question?

4 0

3 years ago

Why freezer is made in the upper part of refrigrator

svp [43]

<h2>Question</h2>

why freezer is made in the upper part of refrigrator

<h2>✒ Answer</h2>

the cold air produced from it is denser than the warmer air in the bottom

<h3>Explaination</h3>

Freezer is normally provided at the top of the refrigerator, because density of the cold air is high compared to the hot air. In a refrigerator the air contacts with the cooling coil and gets cooling.Because of the high density the cold air gets down and the warm air/hot air moves upward and gets cooling from the cooling coil/evaporator coil. This process is repeated. If the Freezer is provided at the bottom place of the refrigerator, the cold air can't to move full area of the refrigerator. So the freezer is normally provided at the top at the refrigerator

4 0

2 years ago

What must be the pressure difference between the two ends of a 2.6 km section of pipe, 36 cm in diameter, if it is to transport

ad-work [718]

Answer: $1.13(10)^{3} Pa$

Explanation:

This problem can be solved by the following equation:

$\Delta P=\frac{8 \eta L Q}{\pi r^{4}}$

Where:

$\Delta P$ is the pressure difference between the two ends of the pipe

$\eta=0.20 Pa.s$ is the viscosity of oil

$L=2.6 km=2600 m$ is the length of the pipe

$Q=900 \frac{cm^{3}}{s} \frac{1 m^{3}}{(100 cm)^{3}}=0.0009 \frac{m^{3}}{s}$ is the Rate of flow of the fluid

$d=36 cm=0.36 m$ is the diameter of the pipe

$r=\frac{d}{2}=0.18 m$ is the radius of the pipe

Soving for $\Delta P$ :

$\Delta P=\frac{8 (0.20 Pa.s)(2600 m)(0.0009 \frac{m^{3}}{s})}{\pi (0.18 m)^{4}}$

Finally:

$\Delta P=1135.26 Pa \approx 1.13(10)^{3} Pa$

7 0

3 years ago

What is not an essential part of isolated soldier guidance

mel-nik [20]

Answer:

Option B, visual sightings

Explanation:

Options for the question are

A) accountability mechanism

B) visual sightings

C) intelligence

D) surveillance

E) reconnaissance operations, or communications

Solutions

The Fundamentals of Army Personnel Recovery (PR) outlines certain circumstances under which a person has to undergo survival situation thereby taking the necessary steps to avoid capture and return safely to their respective unit.

An isolated soldier is expected to know where they are, upcoming route and rally points. They are supposed to know the near and far recognition signals, recovery site protocols, challenge and password etc. A proper preparation is to be done for this including planning, medicines, kits, etc.

Visual sightings is not an essential part of isolated PR

Hence, option B is correct

4 0

3 years ago