You are outdoors when you hear the constant chirp of a still cricket. You start walking toward the cricket and at some point you
1 answer:
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Explanation:
Given
initial velocity(v_0)=1.72 m/s
using
Where v=final velocity (Here v=0)
u=initial velocity(1.72 m/s)
a=acceleration
s=distance traveled
s=0.214 m
(b)time taken to travel 0.214 m
v=u+at
t=0.249 s
(c)Speed of the block at bottom
Here u=0 as it started coming downward
v=1.72 m/s
Answer:
The charged particle will follow a circular path.
Explanation:
The magnetic force exerted on the charged particle due to the magnetic field is given by:
where
q is the charge
v is the velocity of the particle
B is the magnetic field
is the angle between v and B
In this problem, the velocity is perpendicular to the magnetic field, so and the force is simply
Moreover, the force is perpendicular to both B and v, according to the right-hand rule. Therefore, we have:
- a force that is always perpendicular to the velocity, v
- a force which is constant in magnitude (because the magnitude of v or B does not change)
--> this means that the force acts as a centripetal force, so it will keep the charged particle in a uniform circular motion. So, the correct answer is
The charged particle will follow a circular path.
Answer:
(a) the compression of the spring when the block comes to rest is 4cm
(b) speed of the block is 0.427 m/s
Explanation:
Given;
mass of the block, m = 1.6 kg
spring constant, k = 902 N/m
initial speed of the block, v₀ = 0.95 m/s
(a) the compression of the spring when the block comes to rest
when the block comes to rest, the final speed, vf = 0
Apply the law of conservation of energy;
¹/₂kx² = ¹/₂mv₀²
kx² = mv₀²
x = 4 cm
(b) speed of the block
Apply the law of conservation of energy;
¹/₂mv² = ¹/₂kx²
mv² = kx²