Answer:
18.37 is the answer so it should be 18.4
Step-by-step explanation:
Copper: Nickel = 4:1
a) How much copper needed for 20 kg nickel
C:N = 4: 1
C:20 = 4:1
C/20 = 4/1 Cross Multiply
C*1 = 4*20
C = 80
80kg Copper would be needed.
b) How much Nickel would be needed for 20 kg of Copper
C:N = 4: 1
20:N = 4:1
20/N = 4/1 Cross Multiply
4*N = 1*20
4N = 20 Divide both sides by N.
N = 20/4 = 5
5kg Nickel would be needed.
First isolate the power of 10 on the right side by dividing both sides by 5:
Now you're free to take the logarithm and simplify where you can:
Then solve for :
At first glance, it might be tempting to say this is a linear function, because we see linear terms (3x and –6x); however, these are multiplied together, so it's actually a quadratic.
We need to expand the function (hint: use FOIL) to identify the terms.
The x^2-term, or quadratic term, is
. The x-term, or linear term, is
. The number term, or constant term, is –20.
Desmos comes in handy with these problems. Use the "FOIL" method for each of them and then plug them into the calculator of desmos. This will graph each other them. Note the x and y axis'
Example for (A) y= (x-2)(x+3) foil it:
x^2+3x-2x-6
x^2+x-6
plug that in and match to graph.