What are the zeros of the polynomial function?

A plumber charges $15 for a service call plus $20 per hour of service. Write an equation in slope-intercept form for the cost, y

artcher [175]

Answer:

Y=20x+15 & 175 dollars

Step-by-step explanation:

The word problems says $20 per hour, so that means 20 times the amount of hours. If yo multiply 20 times 8 you get 160. Add 15 to 160, you end up with $175.

6 0

3 years ago

Evaluate:<br> 8 to the 8/3 power

KIM [24]

The answer is 256 hope this helps :)

5 0

3 years ago

Read 2 more answers

What is the surface area of this figure

baherus [9]

Answer:

789_278913_97/1_397/_317074

Step-by-step explanation:

gvyhfeuoyefbhbhioevfbebo no ohef. ve h hoierv wfv hirev ihoev si o w our w h. while vhio f hio

8 0

3 years ago

Use the discriminant to determine what type of roots the equations will have, and categorize the equations according to their ro

topjm [15]

Step-by-step explanation:

The discriminant of the quadratic equation $ax^2+bx+c=0$ :

$\Delta=b^2-4ac$

If Δ < 0, then the equation has two complex roots $x=\dfrac{-b\pm\sqrt\Delta}{2a}$

If Δ = 0, then the equation has one repeated root $x=\dfrac{-b}{2a}[/tex If Δ > 0, then the equation has two discint roots [tex]x=\dfrac{-b\pm\sqrt\Delta}{2a}$

$1.\ x^2-4x+2=0\\\\a=1,\ b=-4,\ c=2\\\\\Delta=(-4)^2-4(1)(2)=16-8=8>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=2\sqrt2\\\\x=\dfrac{-(-4)\pm2\sqrt2}{2(1)}=\dfrac{4\pm2\sqrt2}{2}=2\pm\sqrt2\\\\==============================\\\\2.\ 5x^2-2x+3=0\\\\a=5,\ b=-2,\ c=3\\\\\Delta=(-2)^2-4(5)(3)=4-60=-56$

$3.\ 2x^2+x-6=0\\\\a=2,\ b=1,\ c=-6\\\\\Delta=1^2-4(2)(-6)=1+48=49>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt{49}=7\\\\x=\dfrac{-1\pm7}{(2)(2)}\\\\x_1=\dfrac{-8}{4}=-2,\ x_2=\dfrac{6}{4}=\dfrac{3}{2}\\\\==============================\\\\4.\ 13x^2-4=0\qquad\text{add 4 to both sides}\\\\13x^2=4\qquad\text{divide both sides by 13}\\\\x^2=\dfrac{4}{13}\to x=\pm\sqrt{\dfrac{4}{13}},\ \bold{two\ distinct\ roots}\\\\==============================$

$5.\ x^2-6x+16=0\\\\a=1,\ b=-6,\ c=16\\\\\Delta=(-6)^2-4(1)(16)=36-64=-28$

$7.\ 4x^2+11=0\qquad\text{subtract 11 from both sides}\\\\4x^2=-11\qquad\text{divide both sides by 4}\\\\x^2=-\dfrac{11}{4}\to x=\pm\sqrt{-\dfrac{11}{4}}\\\\x=\pm\dfrac{\sqrt{11}}{2}\ i,\ \bold{two\ complex\ roots}$

6 0

3 years ago

Read 2 more answers

.A retailer sold two articles at same price. He sold the first one at 10% profit and the

IRISSAK [1]

Step-by-step explanation:

so let's assume they both sold for 100 each the first article sold for 10% laws there by cost of article is 111.11 rounded the second article made 25% profit so cost must be 80 total cost is 8.89 or 5% profit I'm so sorry if im wrong

3 0

3 years ago