Answer:
A.
Step-by-step explanation:
A for apple....
Dwuhhhhhhhhhhhhh
Isss ezeewer dan anytwing
Step-by-step explanation:
sorry it's not clear.
thank you
Answer: 6% decrease
Step-by-step explanation:
Answer:
The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Step-by-step explanation:
This is an example of logistic equation on population growth
carrying capacity, k = 200
Rate, r = 3% = 0.03
Initial Population, P1 = 80
P(t) =?
P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))
P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))
= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))
= 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Answer:
B
Step-by-step explanation:
given the 2 equations
y - 4x = 12 → (1)
2 - y = 2(x + 2)² → (2)
rearrange (1) expressing y in terms of x
y = 12 + 4x
Simplify (2) by expanding factor and substituting y = 12 + 4x
2 - (12 + 4x) = 2(x² + 4x + 4)
2 - 12 - 4x = 2x² + 8x + 8
- 10 - 4x = 2x² + 8x + 8 ← rearrange into standard form
add 10 + 4x to both sides
2x² + 12x + 18 = 0 ← in standard form
divide through by 2
x² + 6x + 9 = 0
(x + 3)(x + 3) = 0 ⇒ (x + 3)² = 0 ⇒ x = - 3
Point of intersection = (- 3, 0 ) → B
