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Eva8 [605]
3 years ago
10

What is 3x3 – 11x2 – 26x + 30 divided by x – 5?

Mathematics
2 answers:
ahrayia [7]3 years ago
8 0
Hello :
 3x3 – 11x2 – 26x + 30 divided by x – 5 is :<span>3x2 + 4x – 6
because :
(x-5)(3x²+4x-6)=3x^3+4x²-6x-15x²-20x+30 =</span>3x3 – 11x2 – 26x + 30
Karo-lina-s [1.5K]3 years ago
7 0
The answer is letter B. I just had this question on my last lesson!

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Answer:

The answer is 10.

Step-by-step explanation:

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Express 3/8 in thirty-seconds
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The answer is 12/32 i believe.
6 0
3 years ago
Use Lagrange multipliers to find the volume of the largest rectangular box in the first octant with three faces in the coordinat
tensa zangetsu [6.8K]

Answer:

The volume of the largest rectangular box (V) = 81/4

Step-by-step explanation:

<u>Step 1</u>:-

Given volume of the largest rectangular box in the first octant

V = l b h

let (x ,y, z) be the one vertex in the given plane

V = f(x, y, z) = x y z

given plane.   Ф (x, y, z) = x + 9y + 4z = 27 ........(1)

<u>Step( ii):</u>

By using  Lagrange multipliers

Suppose it is required to find the extreme for the function f(x, y, z) subject to the condition Ф (x, y, z) =0

Form Lagrange function F(x, y, z) = f(x, y, z) + λ  Ф (x, y, z) where λ is called the Lagrange multipliers

F(x, y, z) = x y z+ λ ( x + 9y + 4z - 27) ......(2)

Obtain the equations are δ F / δ x = 0

                                  δ f / δ x +λ  δ Ф  / δ x =0

                           ⇒ y z + λ ( 1) = 0

                          ⇒ y z = - λ ......(a)

Obtain the equations are δ F / δ y = 0

                            δ f / δ x +λ  δ Ф  / δ x =0

                        ⇒ x z + λ ( 9) = 0

                        ⇒ \frac{xz}{9} = - λ .......(b)

Obtain the equations are δ F / δ z = 0

                                  δ f / δ x +λ  δ Ф  / δ z =0

                                   x y + λ ( 4) = 0

                                    ⇒ \frac{xy}{4} = - λ .......(c)

<u>Step (iii):-</u>

Equating (a) and (b) equations

we get         y z = \frac{xz}{9}

cancel 'z' value we get  x = 9y  .......(d)

Equating (b) and (c) equations

we get     \frac{xy}{4}  = \frac{xz}{9}

cancel 'x' value on both sides , we get

              4z =9y  ......(e)

substitute (d) (e) values in equation (1)  we get

x + 9y + 4z -27 = 0

9y + 9y + 9y -27 =0

27y -27 =0

<u> y = 1</u>

substitute y =1 in x = 9y

<u>x = 9</u>

substitute y =1 in 4z =9y

<u>z = 9 /4</u>

therefore the dimensions are x =9 , y=1 and z = 9 /4

<u>Conclusion</u>:-

The largest volume of the rectangular box V = x y z

substitute x =9 , y=1 and z = 9 /4

V = 9(1)(9/4) =81/4

The largest volume of the rectangular box (V) = 81/4

Verification :-

Given plane x + 9y + 4z = 27

substitute x =9 , y=1 and z = 9 /4

              9 + 9 + 4(9/4) = 27

           27 =27

so satisfied equation

     

3 0
3 years ago
There is 20 students in mr.millers algebra class. 14 of the students are females. if mr.miller selects a student at random, what
Romashka [77]
7/10 or 70%!!

Hope this helps (:
5 0
3 years ago
Solve 100 ÷ 5 × 4 + 43<br> A. 69 <br> B 144<br> C 0.3<br> D 1.2
Liula [17]
100/5= 20
20 x 4 = 80
80 + 43 = 123

if my math is correct then none are correct
(prolly a typo)
7 0
3 years ago
Read 2 more answers
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