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1 year ago

Simplify and determine the coefficient of (-2/5x)(5y)(-2x).

Mathematics

1 answer:

Juli2301 [7.4K]1 year ago

4 0

Solution/Answer : 4

Solution: the first you do is multiply the last two parentheses to get -10xy

Now we are left with ( -2/5x)(-10xy)
Then we multiply that out into
(-2*-10)/5*x^2y = 20/5x^2y =
4x^2y

The coefficient in this case would be four. (In case you were confused about what a coefficient actually is, it’s the number you multiply a variable by)

Hopes this helps :)

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A central angle θ in a circle of radius 4 m is subtended by an arc of length 5 m. find the measure of θ in degrees. (round your

koban [17]

Answer:

$\theta=71.6\°$

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference is equal to

$C=2\pi r$

we have

$r=4\ m$

substitute the values

$C=2\pi (4)=8 \pi\ m$

step 2

Remember that

360 degrees subtends the arc of length $8 \pi\ m$ (circumference)

by proportion

Find the measure of θ by an arc of length 5 m

assume $\pi=3.1416$

$\frac{360}{8\pi}=\frac{\theta}{5}\\ \\ \theta=360*5/8\pi \\ \\ \theta=71.6\°$

5 0

2 years ago

Hi can someone help me with this

Ad libitum [116K]

Answer:

25 units

Step-by-step explanation:

Applying Pythagoras' Theorem,

(BD)^2= (CD)^2 + (BC)^2

(BC)^2= 65^2 - 60^2

(BC)^2= 625

BC= √625= 25

5 0

2 years ago

The center of a circle is at (−3, 1) and its radius is 9.

pickupchik [31]

Answer:

Sorry but the correct answer is (x+3)2+(y−1)2=81

Step-by-step explanation:

Because the radius squared is the answer of the equation

4 0

2 years ago

Phantasy [73]

Answer:

-19/9

Step-by-step explanation:

First, you would plug in the numbers for y and r. Therefore, your equation should now be 5 = 9x + 24. Now you would put like terms on the same side. It now then look like -19 = 9x. You divide by 9 to get the x by itself. The answer should be x = -19/9.

5 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

2 years ago