Answer:(a) getting the equation:
We'll assume that the altitude is represented by the x-axis and that the boiling point is represented by the y-axis.
Therefore, we have two given points:
(8400 , 200.4) and (4200 , 206.7)
Since the relation is linear, therefore, the graph forms of straight line with the general equation:
y = mx + c where m is the slope and c is the y-intercept.
First, we will calculate the slope:
m = (y2-y1) / (x2-x1) = (206.7 - 200.4) / (4200 - 8400) = -0.0015
Therefore, the equation of the line now is:
y = -0.0015x + c
Then, we will need to calculate the y-intercept. In order to do so, we will use any give point and substitute in the previously obtained equation as follows:
y = -0.0015x + c
206.7 = -0.0015(4200) + c
c = 213
Based on the above calculations, the equation of the line is:
y = -0.0015x + 213
(b) getting the boiling point at altitude = 2100 ft:
Now, in order to calculate the boiling point at altitude 2100, we will substitute in the equation of the line as follows:
y = -0.0015(2100) + 213 = 209.85 degrees Fahrenheit
Step-by-step explanation:
is 9/8 so its 3 poles