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VARVARA [1.3K]
2 years ago
9

URGENT Enter the values for the highlighted variables that show how to subtract the rational expressions correctly: StartFractio

n 2 Over x squared minus 36 EndFraction minus StartFraction 1 Over x squared + 6 x EndFraction = StartFraction 2 Over (x + 6) (x minus 6) EndFraction minus StartFraction 1 Over x (x + a) EndFraction. = StartFraction b x Over (x + 6) (x minus 6) x EndFraction minus StartFraction x minus c Over (x + 6) (x minus 6) x EndFraction. = StartFraction d x minus x + e Over (x + 6) (x minus 6) x EndFraction. = StartFraction x + f Over (x + 6) (x minus 6) x EndFraction. = StartFraction g Over x (x minus 6) EndFraction a = b = c = d = e = f = g =
Mathematics
1 answer:
Marrrta [24]2 years ago
3 0

The value of the highlighted variables ave been determined a =6, b= 2 ,c= 6 , d = 2  , e = 6 , f = 6, g =1

<h3>What is an Expression ?</h3>

An expression are mathematical statement consisting of variables , constants and mathematical operators .

The given expression is

\rm \dfrac{2}{x^2-36} - \dfrac{1}{x^2 +6x} = \dfrac{2}{(x+6)(x-6)}-\dfrac{1}{x(x+a)}\\\\= \dfrac{bx}{x(x+6)(x-6)}-\dfrac{x-c}{(x+6)(x+6)x}\\\\= \dfrac{dx-x+e}{x(x+6)(x-6)}\\\\= \dfrac{x+f}{x(x+6)(x-6)}\\\\= \dfrac{g}{x(x-6)}

a = 6

b= 2

c= 6

d = 2

e = 6

f = 6

g =1

Therefore the value of the highlighted variables ave been determined.

To know more about Expression

brainly.com/question/14083225

#SPJ1

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Solve by substitution. Show each step of your work.<br><br> 2x + y = 7<br><br> 3x + 5y = 14
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Alright...simple...showing all steps.. ;)

You have the equations...

2x+y=7
and
3x+5y=14

To be able to even solve for any of the variables...multiply the equations by...2...and..3...

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=========

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A sequence is defined recursively by the following rules: f(1)=3f(n+1)=2⋅f(n)−1 Which of the following statements is true about
Radda [10]

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Step-by-step explanation:

The given formula, that recursively defines the sequence is

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When n=3,

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When n=4

f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33

When n=5,

f(6) = 65

4 0
3 years ago
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