What is 8 1/2 divided by 12?

Simplify:3/4-1/3+1/12

goblinko [34]

Answer:

1/2

Step-by-step explanation:

5/12+1/12

=1/2

Here u goo hope it helps :))

4 0

3 years ago

Read 2 more answers

The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q

Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

$\frac{\sum f}{4}=\frac{100}{4}=25$

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

$Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h$

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF) $_{p}$ = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

$Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h$

$=34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75$

The value of first quartile is 34.75.

Q₃ is at the position:

$\frac{3\sum f}{4}=\frac{3\times100}{4}=75$

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

$Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h$

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF) $_{p}$ = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

$Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h$

$=44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83$

The value of third quartile is 44.83.

Then the inter-quartile range is:

$IQR = Q_{3}-Q_{1}$

$=44.83-34.75\\=10.08$

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

$P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}$

$=\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89$

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0

4 years ago

The precision of a voltmeter is ±0.005 V. The accepted value for a measurement is 9.016 V. Which measurement is in the accepted

Westkost [7]

Since the precision of the voltmeter is <span>±0.005 V, the effective value range for the first measurement is 9.000 V to 9.010 V, for the second it is 9.001 V to 9.010 V, the third 9.013 V to 9.023 V and the fourth 9.021 V to 9.030 V. From all of these measurements the only one which the accepted value falls within the range is measurement 3.</span>

4 0

3 years ago

Read 2 more answers

A national survey indicated that 50% of adults conduct their banking online. It also found that 20% are younger than 50, and

Arisa [49]

Answer:

The probability that a person is younger than 50 given that she uses onling banking is 1.5%

Step-by-step explanation:

The survey indicated that 50% of adults conducts their banking online.

P(online banking customers) =1/2

Of the total number of customer that bank online, the survey stated that 20% of them are younger than 50 years.

P(customers younger than 50 yrs) =1/5

Out of the 20% than are younger than 50, we were told that 15% of them conduct online banking.

P(younger than 50 online banking customer) =3/20

Therefore the the probability that a = person is younger than 50 given that she uses online banking is P = 3/20*1/5*1/2 =17==3/200 = 0.015 =1.5%

The probability that she is younger than 50 does not increase or decrease with additional information, it only makes it clearer.

3 0

4 years ago

If there are 25 students in a class in which 5 of the 11 guys wear glasses and 6 out of the 14 girls wear glasses- what is the p

DochEvi [55]

Answer:

6 out of 25

Step-by-step explanation:

3 0

3 years ago