The solution of the system of equations means that following:
1- In case we are dealing with system of equations, the solution would be the point of intersection of the two graphs
2- In case we're dealing with only one equation, the solution would be the points of intersection of the graph with the x-axis
Graph (a):
The graph is for a system of equations (two lines). Therefore, the solution would be the point of intersection of the two lines.
From the graph, we can note that there is only one point of intersection between the two lines (-3,-1). Therefore, the system of equations has only one solution
Graph (b):
The graph is for a system of equations (two lines). Therefore, the solution would be the point of intersection of the two lines.
From the graph, we can note that the two lines are parallel. This means that they will never intersect. Therefore, the system of equations has no solutions
Graph (c):
The graph is for a single line. Therefore, the solution(s) would be the point(s) that make the overall equation equal to zero, i.e. point(s) of intersection with the x-axis.
From the graph, we can note that the line intersects with the x-axis only once at point (2,0). This means that the line has only one solution.
Hope this helps :)
Answer:
1) The system of equations is 
and 
2) The first number is 
and the second number is 
Step-by-step explanation:
1) Let be "x" the first number and "y" the second number.
Remember that:
a- The word "times" indicates multiplication.
b- A sum is the result of an addition.
c- "Is" indicates this sign: 
Then, the sum of 5 times "x" and 4 times "y" is 75, can written as:
And "The sum of the two numbers is 18" can written as:
Therefore, the System of equations is:
2) You can use the Elimination Method to solve it:
- Multiply the second equation by -5, add the equations and then solve for "y":
- Substitute the value of "y" into any original equation and solve for "x":
Answer:
the largest block represents the hypotenuse which would be c² the smallest can either be a or b and the block thats left over will be the letter you didn't use for the small block so in terms the blocks represents a²+b²=c²
S= 13/5 is the answer
I hope it’s help u !
"determine the location" or namely, is it inside the circle, outside the circle, or right ON the circle?
well, we know the center is at (1,-5) and it has a radius of 5, so the distance from the center to any point on the circle will just be 5, now if (4,-1) is less than that away, is inside, if more than that is outiside and if it's exactly 5 is right ON the circle.
well, we can check by simply getting the distance from the center to the point (4,-1).
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ \stackrel{center}{(\stackrel{x_1}{1}~,~\stackrel{y_1}{-5})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[4-1]^2+[-1-(-5)]^2}\implies d=\sqrt{(4-1)^2+(-1+5)^2} \\\\\\ d = \sqrt{3^2+4^2}\implies d =\sqrt{9+16}\implies d=\sqrt{25}\implies \stackrel{\textit{right on the circle}}{d = 5}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20%5Cstackrel%7Bcenter%7D%7B%28%5Cstackrel%7Bx_1%7D%7B1%7D~%2C~%5Cstackrel%7By_1%7D%7B-5%7D%29%7D%5Cqquad%20%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B-1%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%20%3D%20%5Csqrt%7B%5B4-1%5D%5E2%2B%5B-1-%28-5%29%5D%5E2%7D%5Cimplies%20d%3D%5Csqrt%7B%284-1%29%5E2%2B%28-1%2B5%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20d%20%3D%20%5Csqrt%7B3%5E2%2B4%5E2%7D%5Cimplies%20d%20%3D%5Csqrt%7B9%2B16%7D%5Cimplies%20d%3D%5Csqrt%7B25%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bright%20on%20the%20circle%7D%7D%7Bd%20%3D%205%7D)
