If Pepsin and Trypsin had to function together, which PH would produce the highest activity? How is this answer found?
2 answers:
You might be interested in
Answer:
<u>In the mitochondrial matrix</u>
<u></u>
Explanation:
The mitochondria is an organelle within the cytoplasm of the cell. It consists of an outer membrane, inner membrane, and matrix containing a gel-like substance. During aerobic respiration in mitochondria, cells break down sugars in the form of glucose into (carbon dioxide) and
(water) to obtain energy in the form of ATP or adenosine triphosphate.
aerobic respiration:
C6H12O6+ 6 O2 → 6 CO2 + 6 H2O + ≅38 ATP
(glucose) (oxygen) (carbon dioxide) + (water)
The Kreb's cycle involves several enzymatic reactions, where pyruvate derivatives obtained from glycolysis, are reduced and oxidized to harvest energy as ATP.
So I don’t see answer choices here, but your answer is 50% of the offspring will be homozygous dominant with RR, and 100% of them will carry a homozygous dominant gene of Rr
If you take the two sets and put them into a punnett square, it would look like this (image attached):
When the two sets of alleles are crossed, you would end up with half of your pairs being fully dominant (RR), and the other half being dominant while containing a recessive gene (Rr). Since there’s only one recessive gene in these pairs, it gets overridden and the pair itself is dominant.
So your answer is 50% will be homozygous dominant with RR!
If you take the two sets and put them into a punnett square, it would look like this (image attached):
When the two sets of alleles are crossed, you would end up with half of your pairs being fully dominant (RR), and the other half being dominant while containing a recessive gene (Rr). Since there’s only one recessive gene in these pairs, it gets overridden and the pair itself is dominant.
So your answer is 50% will be homozygous dominant with RR!