Class or type of animal herbivore, carnivore, and decompress <span />
Im guessing it is due to gene shuffling
Ethyl alcohol and carbon dioxide are the end products of Alcoholic fermentation.<span />
Answer:
in spanish-Los términos embrión y feto se refieren al bebé en desarrollo dentro del útero de la madre. ... Un embrión se denomina feto a partir de la undécima semana de embarazo, que es la novena semana de desarrollo después de la fertilización del óvulo. Un cigoto es un organismo unicelular resultante de un óvulo fertilizado.
Explanation:
in english- The terms embryo and fetus both refer to the developing baby inside the mother's womb (uterus). ... An embryo is termed a fetus beginning in the 11th week of pregnancy, which is the 9th week of development after fertilization of the egg. A zygote is a single-celled organism resulting from a fertilized egg.
Answer:
See the explanation
Explanation:
Answer 1.
As given that in F1 all are short and white then it can be said according to Mendel's law that short and white are dominant over tall and purple.
Let S for short s for tall and W for white and w for purple allele.
So the genotype of short purple will be Ssww or SSww. So In first case Ssww self crossed then resultant offsprings will be,
................ Sw .................... sw
Sw ........ SSww ............. Ssww
sw ........ Ssww .............. ssww (tall and purple)
So from this 1/4 will be tall and purple while 3/4 will be short and purple.
In second case SSww only short purple progeny will appear.
Answer 2.
2. a) The female progeny will not show any trait because there are two X chromosome in females , so female offspring can be carrier but not show any trait in case of X- linked trait.
2. b) Half of male offsprings show trait because X is inherited from mother. So the chance of having X-linked recessive allele is 1/2.
2. c) The chance of having X linked affect allele in daughter is 1/2. So the chance of inheriting that X to son will be 1/2 so in total there is chance of 1/4 that son will be affected.
2. d) the chance of first child show this trait will be 1/4 in case of male offspring while 0 in case of female offspring.
Hope this helps!
