The period is 5 on this graph
It is a sinusoidal graph, which oscilates around the x-axis (y=0), from y = -0.5 to y = 0.5
General description (as reference)
It passes through the origin (0,0), increases until the max value (y = 0.5) when x = π6, then start to decrease, crosses the x-axis x = π/3, continues decreasing until the min value (y = -0.5) when x = 2π/3, then it starts to increase, crossing the x-axis again at x = 2π/3, and the pattern repeats indefinetely to the right of x = 2π/3 and to the left of x = 0.
Specific description:
Amplitud: 0.5----> the coefficient in front of the sine function
Period: 2π/3 ----> 2π divided by the coefficient in front of the argument (3)
Points of intersection with the x-axis: 0 + /- nπ/3, with n = 0,1,2,3,.....
Type of function: odd
Maximun value: 1/2
Minimum value: -1/2
Answer:
So a batch is 5/8
There are THREE 3/4th cups of flour in the cupboard.
So 3 three fourths so basically
3/4 * 3 = 9/4 or
3/4 + 3/4 + 3/4 = 9/4
9/4 and each batch is 5/8.
9/4 ÷ 5/8 = 72/20 or 3 1/10
3 batches of cookies.
Answer:
a = 6, b = 8, and c = 10.
Step-by-step explanation:
You can easily use the Pythagorean Theorem to solve all of these.
a = 4; b = 6; c = 8... 4^2 + 6^2 = 16 + 36 = 52. 8^2 = 64. 52 is not equal to 64, so the first choice is not a right triangle.
a = 6; b = 8; c = 10... Well this is a multiple of the 3-4-5 Pythagorean triple, so this is a right triangle.
a = 5; b = 6; c = 761... 5^2 + 6^2 = 25 + 36 = 61. 761^2 = 579121, which is not equal to 61, so the third choice is not a right triangle.
a = 6; b = 9; c = 12... 6^2 + 9^2 = 36 + 81 = 117. 12^2 = 144, which is not equal to 117, so the fourth choice is not a right triangle.
The only case where there is a right triangle is the second choice, where a = 6, b = 8, and c = 10.
Hope this helps!
you search the LCD then you subtracted the top and left the bottom the same
Step-by-step explanation:
im not sure
