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seropon [69]
3 years ago
12

Problem page three consecutive even integers have a sum of 36 . find the integers.

Mathematics
1 answer:
ANTONII [103]3 years ago
6 0
3 consecutive even integers = 36 .
ANSWER 10+12+14= 36
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What can you conclude about the population density from the table provided? Population Area (km²) Region A 20,178 521 Region B 1
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2 years ago
F(x)= √x-5. find f-2
rodikova [14]

For this case we have:

Be a function of the form y = f (x)

Where:

f (x) = \sqrt {x-5}

If we want to find f (-2), we substitute x = -2, then:

f (-2) = \sqrt {-2-5}\\f (-2) = \sqrt {-7}

Since we have a negative root, the result will be given by complex numbers. By definition:

\sqrt {-1} = i

So:

f (-2) = \sqrt {7} i

Answer:

f (-2) = \sqrt {7} i


3 0
4 years ago
$5 PAYPAL + BRAINLIEST TO ANSWER THS
expeople1 [14]

Answer:

Quadratic Equation:

3x^2=2x +5

\text{Standard Form: } 3x^2-2x-5=0

From the standard form of a Quadratic Function, we get:

a=3,\:b=-2,\:c=-5

Discriminant:

\Delta=\left(-2\right)^2-4\cdot \:3\left(-5\right)

\Delta=\left(-2\right)^2+4\cdot \:3\cdot \:5

\Delta=64

From the discriminant, we conclude that the equation will have two real solutions.

State that:

b^2-4ac

b^2-4ac =0:\text{The equation has 1 real solution}

b^2-4ac >0:\text{The equation has 2 real solutions}

By the way, solving the equation given:

$x=\frac{2\pm\sqrt{64}}{2\cdot \:3}$

$x=\frac{2\pm\sqrt{64}}{6}$

$x=\frac{2\pm8}{6}$

$x_{1} =\frac{10}{6}=\frac{5}{3}  $

$x_{2}=\frac{-6}{6} =-1$

5 0
3 years ago
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