2x^2 + 4x + 1 = 0
2x^2 + 4x + 1 - 1 = 0 - 1
2x^2 + 4x = -1
X(2x + 4) = -1
X = -1.
2x + 4 = -1
2x + 4 - 4 = -1 - 4
2x = -5
2x/2 = -5/2
X = -5/2.
I believe these are the solutions. If not you can use the quadratic formula to solve for the roots, solutions.
Answer:
Step-by-step explanation:
Hello!
You have two populations of interest and want to compare them. If you define the study variables as:
X₁: average hourly wages of an employee of the Downtown store.
n₁= 25
X[bar]₁= $9
S₁= $2
X₂: average hourly wages of an employee of the North Mall store.
n₂= 20
X[bar]₂= $8
S₂= $1
Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:
95% CI for μ₁ - μ₂
(X[bar]₁-X[bar]₂) ± 


Sa= 1.64

(9-8)±2.017*
[0.007636;1.9923]
I hope it helps!
f(x) = (x + 5)(x - 1)
using the ' factor theorem '
given x = a is the root of a polynomial then (x - a ) is a factor
here roots are x = - 5 and x = 1 hence factors are (x + 5) and (x - 1)
the polynomial is the product of the factors
f(x) = (x + 5)(x - 1)
<span>x+y= 375 y=2x-60
A is the answer </span><span />