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Ghella [55]
3 years ago
6

Statistics endeavors to:

Mathematics
1 answer:
Aleks04 [339]3 years ago
8 0

Answer:

c

Step-by-step explanation:

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Answer:

3x

Step-by-step explanation:

cuz im not dumb

4 0
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I need help with this​
Oxana [17]

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I believe it's the third option

I could be wrong, so sorry if it's not correct.

Step-by-step explanation:

4 0
2 years ago
To compute a19 mod N, the modular exponential algorithms that we studied would do 8 modular multiplications (5 squarings and 3 m
IRINA_888 [86]

Answer:

Answer for the question:

To compute a19 mod N, the modular exponential algorithms that we studied would do 8 modular multiplications (5 squarings and 3 multiplications by a). What is the minimum number of modular multiplications needed to compute a19 mod N if you are free to use any sequence of modular multiplications.)

is given in the attachment.

Step-by-step explanation:

Download pdf
8 0
2 years ago
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Natalka [10]
This is the graph, on the x and y axis od the graph you plot the point at 4 (positive)

4 0
2 years ago
Determine if this relationship forms a direct variation. Verify your answer.
leva [86]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=k or y=kx

so


we have

a) for x=1 y=0.50--------> y/x=0.50/1------> 0.50

b) for x=2 y=1--------> y/x=1/2-------> 0.50

c) for x=3 y=1.50--------> y/x=1.50/3-----> 0.50

d) for x=5 y=2.50--------> y/x=2.50/5----> 0.50

the value of k is equal to 0.50

so

<span>the relationship forms a direct variation. </span>

the equation is

y=0.50*x


Verify

for x=1

y=0.50*(1)------> y=0.50-----> is correct


for x=2

y=0.50*(2)------> y=1.00-----> is correct


for x=3

y=0.50*(3)------> y=1.50-----> is correct


for x=5

y=0.50*(5)------> y=2.50-----> is correct

4 0
2 years ago
Read 2 more answers
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