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kramer
3 years ago
11

Solve the equation by extracting the square roots. when a solution is irrational, list both the exact solution and its approxima

tion rounded to two decimal places.
Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
The polynomial that is given here in which the goal is to find out the roots of the equation is <span>x2 = 196  where x is the root of the equation. we transform the given equation into its standard form that is x^2 - 196 = y in which y should be equal to 0 in order to get x. 
In this case, 

x^2 - 196 = 0 
x^2 = 196
we take the square root of both sides in order to extract x
square root x^2 = square root 196
x = +- 14
there are two roots in this function which are positive and negative numbers.
square of a positive number leads to a positive number while the square of a negative number also yields to a positive number. </span>
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The solution to given system of equations is (x, y) = (\frac{-15}{263} , \frac{-115}{263})

The given equation has one solution

<em><u>Solution:</u></em>

Given system of equations are:

12x - 13y = 5 --------- eqn 1

x = 23y + 10 --------- eqn 2

We have to solve the system of equations by substitution

<em><u>Substitute eqn 2 in eqn 1</u></em>

12(23y + 10) - 13y = 5

276y + 120 - 13y = 5

263y = 5 - 120

263y = -115

y = \frac{-115}{263}

<em><u>Substitute the above value of "y" in eqn 2</u></em>

x = 23 \times \frac{-115}{263} + 10\\\\x = \frac{-2645}{263} + 10\\\\x = \frac{-2645 + 2630}{263}\\\\x = \frac{-15}{263}

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