Answer:
Step-by-step explanation:
Let the total area be x.
<u>Farm exhibits are in 1/10 of the fairground:</u>
<u>Part of the fairground with rides:</u>
- r = x - f = x - 1/10x = 9/10x
<u>How much greater is the part of the fairground with rides than farm exhibits?</u>
- r/f = 9/10x : 1/10x = 9 times
The answer is D because d corolates to angle h
Answer:
40 mph
Step-by-step explanation:
To find the maximum speed at which the car can travel, as the distance it requires to stop is 168 feet, we just need to use the value of d = 168 in the equation, and then find the value of s:
168 = 0.05s^2 + 2.2s
0.05s^2 + 2.2s - 168 = 0
Using Bhaskara's formula: we have:
Delta = 2.2^2 + 4*0.05*168 = 38.44
sqrt(Delta) = 6.2
s1 = (-2.2 + 6.2)/0.1 = 40 mph
s2 = (-2.2 - 6.2)/0.1 = -84 mph (a negative value does not make sense as 's' is the speed of the car)
So the maximum speed of the car is 40 mph
You take 3•4 to get 12, then you add a zero to that and get 120. You then multiply by six and get 720.
