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satela [25.4K]
3 years ago
10

Explain how to write an addition sentence for a picture of 4 rows with 3 items in each row

Mathematics
2 answers:
Evgen [1.6K]3 years ago
5 0
That is 3+3+3+3
Hope it helped
Dahasolnce [82]3 years ago
3 0
The answer would be:
3 + 3 + 3 + 3...
... If you mean what I'm thinking.

:)
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Please help thanks !
Kitty [74]

Answer:

option D

Step-by-step explanation:

x^{2} + y^{2} = 16\\\\x^{2} = 16- y^{2}

equation 2:

\frac{x^{2}}{4} - \frac{y^{2}}{25} = 1

so we have:

\frac{16- y^{2} }{4}-\frac{y^{2}}{25}= 1

7 0
3 years ago
Peter is wants to lose weight. He is105Kg. His aim is to lose 500 g Per week. If he managed this, how many weeks will it be unti
natali 33 [55]

105 - 90 = 15kg

500g = 1/2 kg

Peter is 15kg overweight.

15 x 2 = 30

It will take him 30 weeks for this.

8 0
3 years ago
Which of the following may fall outside a triangle?
algol [13]

Answer: B

Step-by-step explanation:

7 0
2 years ago
How many inflection point(s) do you see ?
dimulka [17.4K]

Answer:

  7

Step-by-step explanation:

There is a point of inflection at each point where the graph crosses the line y=2. There are 7 points of inflection shown.

__

A point of inflection is where the graph changes from being concave downward to concave upward, or vice versa. For a sine function, that is everywhere the function crosses its midline.

6 0
3 years ago
Read 2 more answers
A poll found that 53% of a sample of 1170 teens in a certain large country go online several times a day. (Treat this sample as
posledela

Answer:(a) margin error = 2.4%

(b) The margin error gives the measure in percentage of how the population parameter determined differ from the real population statistics or value.

(c) in 90% of the samples of teens in the country, the percent who go online several times a day will be within 50.6% and 55.4%. of the estimated 100%

Step-by-step explanation:

Using the proportion formulae

Margin error = z √p(1-p)/n

n= 1170, p = 53% = 0.53, 1-p = 0.47

and the z value at 90% C.I = 1.645

M error= 1.645 √0.53×0.47/1170

Margin error = 0.024 = 0.024 ×100

Margin error = 2.4%

53 - 2.4 = 50.6% and 53 + 2.4 = 55.4%

In other words 90% of the time: the number of teens who go online several time a day will be between 50.6 and 55.4%.

8 0
3 years ago
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