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3 years ago

Explain how to write an addition sentence for a picture of 4 rows with 3 items in each row

Mathematics

2 answers:

Evgen [1.6K]3 years ago

5 0

That is 3+3+3+3
Hope it helped

Dahasolnce [82]3 years ago

3 0

The answer would be:
3 + 3 + 3 + 3...
... If you mean what I'm thinking.

:)

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The ratio of the height of a skateboard ramp to the length of the skateboard ramp is 1 to 3.The height of the ramp is 15 feet.Wh

SpyIntel [72]

Answer:

17ft

Step-by-step explanation:

8 0

3 years ago

The perimeter of a triangle is 64cm ,the sides are the ratio 6:5:5 , work out the area of the triangle

Fofino [41]

The area is 192 cm^2

the sides are 20 20 24 with the base being 24

to figure out the height you have to use Pythagorean theorem of the triangle cut in half so 12^2 + b^2 = 20^2
b= 16 = height

b*h* .5= area 16* 24* .5= 192

4 0

3 years ago

The diameter of the circle below is 42 cm. Work out the radius of the circle.

creativ13 [48]

Answer:

r = 21 cm

Step-by-step explanation:

The radius of a circle is 1/2 of the diameter

r = 1/2d

r = 1/2(42)

r = 21 cm

8 0

1 year ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5

DanielleElmas [232]

Answer:

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that $csc(x)=1/sin(x)$ and $sec(x)=1/cos(x)$ .

Thus:

$\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}$

$=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }$

Let's do the first part first: (Recall how to divide fractions)

$\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}$

For the second term:

$\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}$

So, all together: (same denominator; combine terms)

$\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}$

Note the numerator; it can be derived from the Pythagorean Identity:

$sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)$

Thus, we can substitute the numerator:

$\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1$

Everything simplifies to 1.

7 0

2 years ago

Graph a right triangle with the two points forming the hypotenuse. Using the sides, find the distance between the two points in

pshichka [43]

Answer:

$d=\sqrt{53}$

Step-by-step explanation:

We need to find the distance between two points i.e. (−5,−1) and (−3,−8).

It can be calculated using distance formula as follows :

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

We have, x₁ = -5, x₂ = -3, y₁ = -1 and y₂ = -8

Put all the values,

$d=\sqrt{(-8-(-1))^2+(-3-(-5))^2}\\\\d=\sqrt{49+4}\\\\d=\sqrt{53}$

So, the distance between the points is equal to $\sqrt{53}$

5 0

3 years ago