Answer:
i^32=1
i^25=i
i^86=-1
i^51=-i
Step-by-step explanation:
Follow the Rule of Four of I for this,
i^1=![\sqrt{-1}](https://tex.z-dn.net/?f=%5Csqrt%7B-1%7D)
I^2=-1
I^3=-i
I^4=1
Answer:
see explanation
Step-by-step explanation:
The inverse of a matrix A =
is
=
![\left[\begin{array}{ccc}d&-b\\-c&a\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dd%26-b%5C%5C-c%26a%5C%5C%5Cend%7Barray%7D%5Cright%5D)
If ad - bc = 0 then the matrix has no inverse
A = ![\left[\begin{array}{ccc}11&-5\\3&-1\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%26-5%5C%5C3%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D)
ad - bc = (11 × - 1) - (- 5 × 3) = - 11 - (- 15) = - 11 + 15 = 4 , then
=
= ![\left[\begin{array}{ccc}-0.25&0.75\\-1.25&2.75\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-0.25%260.75%5C%5C-1.25%262.75%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Use PEMDAS, Parenthesis and Exponents, then Multiplication and Division, then Addition and Subtraction, all from left to right in the line. So 68+7=75, and 93+75=168
The prime factorization of 360:
360 = 2·2·2·3·3·5 = 2³ · 3² · 5