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Ne4ueva [31]
3 years ago
7

Javier throws two dice and does not care about the order but only that a 6 and a 5 fall, what is the probability that this will

happen?
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0
Not very much because things don't always happen the way we want them too
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Amy is eight years older than twice her cousin Alicia’s age. The sum of their ages is less than 32. Let x represent Alicia's age
horsena [70]
Ok, so amy is 8 years older than twice alica's age
if amy=y and alica=x
y=8+2x

and sum is less than 32
y+x<32

we can subsitute 8+2x for y in other equation
8+2x+x<32
8+3x<32
minus 8 both sides
3x<24
divide both sides by 3
x<8


the inequality is x<8
4 0
4 years ago
Round 23.546 to the nearest tenth and the nearest hundredth. Explain your thinking.
marysya [2.9K]

Answer:

nearest tenth is 23.5

nearest hundredth is 23.55

Step-by-step explanation:any number more than 5 is rounded up to +1 for the next number so for tenth 23.546= 23.5 and for hundredth 23.546=23.55

5 0
3 years ago
This question is kinda confusing I need help
Marizza181 [45]

Answer:

D) p³ + 2; when p = 3 the number of plants is 29.

Step-by-step explanation:

Illiana cubed (³) the number of original plants, p, in the garden. Then, she added 2 more plants. We will use n for the number of total plants.

So, the equation should be p³ + 2. Substitute our value for p into the equation and solve.

p³ + 2 = n

3³ + 2 = n

27 + 2 = n

29 = n

There are 29 total plants.

The answer, then, is the last option, p³ + 2; when p = 3 the number of plants is 29.

Good luck ^^

3 0
3 years ago
Find the oth term of the geometric sequence 5,--25, 125,
Genrish500 [490]

Given the geometric progression below

5,-25,125,\ldots

The nth term of a geometric progression is given below

T_n=ar^{n-1},\begin{cases}a=\text{first term} \\ r=\text{common ratio}\end{cases}

From the geometric progression, we can deduce the following

\begin{gathered} T_1=a=5 \\ T_2=ar=-25 \\ T_3=ar^2=125 \end{gathered}

To find the value of r, we will take ratios of two consecutive terms

\begin{gathered} \frac{T_2}{T_1}=\frac{ar}{a}=\frac{-25}{5} \\ \Rightarrow r=-5 \end{gathered}

To find the 9th term of the geometric, we will have that;

\begin{gathered} T_9=ar^8=5\times(-5)^8=5\times390625 \\ =1953125 \end{gathered}

Hence, the 9th term of the geometric progression is 1953125

8 0
1 year ago
Help you will get 30 <br> Points
Stells [14]

Answer:

Line A is filling more quickly

Step-by-step explanation:

Hope this helps!!:)

8 0
3 years ago
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