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morpeh [17]
3 years ago
13

How many total atoms are in the compound: C6H12O6 18 6 12 24

Chemistry
2 answers:
Mice21 [21]3 years ago
4 0
D.) There are 24 atoms in total in that compound.....
const2013 [10]3 years ago
3 0
It contains 24 atoms and the name of this compound is glucose an easy trick just add the numbers
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Calculate the pH of a 2.0 M H2SO4 solution.
noname [10]
 <span>H2SO4 gives 2 moles oh H+ per mole of acid 

[H2SO4] = 2M so [H+] = 4M 

pH = -log(4) = -.6 

Therefore, the pH </span><span>of a 2.0 M H2SO4 solution is -0.6
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
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What is the name of the following formula: P4O10
Marysya12 [62]
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2 years ago
State with reasons the most suitable methods for collecting hydrogen​
maxonik [38]

Answer:

Upward delivery or downward displacement of air

Explanation:

The method of collection of a gas is dependent on it's density.

Gases that are less dense than air are collected by upward delivery or downward displacement of air while gases that are denser than air are collected by downward delivery or upward displacement of air.

Hydrogen is less dense than air hence it is collected by upward delivery or downward displacement of air.

7 0
3 years ago
Please help :) hope you have a good day
sineoko [7]

Have a wonderful day :) thanks for the points

3 0
2 years ago
How many joules of heat are needed to raise the temperature of 47.5 g of aluminum from 21°C to 94°C , if the specific heat of al
Montano1993 [528]

Answer:

3120.75J

Explanation:

So, we have the formula q = mc\Delta t. For this example, q is the heat energy in Joules, m is the mass in grams, c is the specific heat capacity in \frac{J}{{g\°C}}, and \Deltat is the change in temperature. In this case, m = 47.5g, c = 0.9  \frac{J}{{g\°C}}, and \Deltat  = 94-21 = 73°C. Plugging in the values, we get the joules of heat required to raise 47.5g of Al from 21°C to 94°C which is stated above. You can double check my answer but that should be it. An important thing to be aware of are the units. Sometimes, the heat capacity may not be \frac{J}{{g\°C}}. I may be in Kelvin or something. Anyways, hope this helps.

5 0
3 years ago
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