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3 years ago

What elements are most commonly used in wiring?

Chemistry

1 answer:

Schach [20]3 years ago

6 0

Answer:

Hi myself Shrushtee.

Explanation:

Wire Materials: The most common material for electrical wire is copper and aluminum, these are not the best conductors however they are abundant and low cost. Gold is also used in applications because it is corrosion resistant.

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Balance this equation- Na3PO4 + KOH -> NaOH + K3PO4

SSSSS [86.1K]

Na3PO4 + 3 KOH = 3 NaOH + K3PO4

3 0

3 years ago

Read 2 more answers

A graduated cylinder is filled 25.0 mL with water and a piece of granite is placed in the cylinder, displacing the level to 37.2

kvv77 [185]

The volume of the granite piece in Cm³ is 12.2 cm³

calculation

volume of granite = (volume of cylinder after placing granite - volume of cylinder before placing granite

= 37.2 ml - 25.0 ml = 12.2 ml

convert ml to Cm³

that is 1 ml = 1 cm³

12.2 ml = ? cm³

by cross multiplication

=(12.2 ml x 1 cm³) / 1 ml = 12.2 cm³

3 0

3 years ago

A student performed a chemical reaction in which 35 grams of hydrogen and 65 grams of oxygen reacted to form water. What is the

sergejj [24]

Answer:

The mass of the product is 73,06 g

Explanation:

The reaction to form water is:

2H2 + O2 ---> 2H2O

35 g 65 g

Molar mass H2 = 2g/m ---> I have 17,5 moles (35g / 2 g/m)

Molar mass O2 = 32g/m ---> I have 2,03 moles (65g / 32g/m)

2 moles of H2 __reacts with __ 1 mol O2

17,5 moles of H2 __ reacts with ___ (17,5 m . 1 m) / 2 m = 8,75 m

I have just 2,03 m of O2 and I need 8,75 m so O2 is my limiting reagent

1 mol of O2 ___ reacts with 2 moles H2

2,03 moles of O2 __ reacts with (2,03 m . 2 m) / 1 m = 4,06 m

I have 17,5 moles of H2 and I need 4,06 m. H2 is my excess reagent

"All operations are done with the limiting reagent"

1 mol O2 are required____ to form 2 H2O

2,03 mol O2 are required __ to form (2,03m . 2m) / 1m = 4,06 m

Molar mass of water: 18 g/m

Mass of water ----> Molar mass . Moles water = 18 g/m . 4,06 m = 73,08g

8 0

3 years ago

A 15.0 ml sample of gas at 10.0 degree Celsius and 760 torr changes to a pressure of 1252 torr at 35.0 degree Celsius. What is t

netineya [11]

Answer:

9.91 mL

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (torr)

P2 = final pressure (torr)

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

V1 = 15.0mL

V2 = ?

P1 = 760 torr

P2 = 1252 torr

T1 = 10°C = 10 + 273 = 283K

T2 = 35°C = 35 + 273 = 308K

Using P1V1/T1 = P2V2/T2

760 × 15/283 = 1252 × V2/308

11400/283 = 1252V2/308

Cross multiply

11400 × 308 = 283 × 1252V2

3511200 = 354316V2

V2 = 3511200 ÷ 354316

V2 = 9.91 mL

4 0

3 years ago

In an experiment magnesium ribbon was heated in air. The product was found to be heavier than the original ribbon. Potassium man

KatRina [158]

Burning a magnesium ribbon in the air is an addition reaction while heating potassium manganate 7 is a decomposition reaction.

<h3>Addition and decomposition reactions</h3>

Magnesium burns in air to produce magnesium oxide as follows:

$2Mg + O_2 --- > 2MgO$

Potassium manganate 7 burns to produce multiple products as follows:

$2 KMnO_4 --- > K_2MnO_4 + MnO_2(s) + O_2$

Thus, the MgO will be heavier than Mg. On the other hand, $MnO_2$ will be less heavy than $KMnO_4$ .

More on reactions can be found here: brainly.com/question/17434463

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7 0

2 years ago