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kakasveta [241]
4 years ago
7

Calculate the pH of a 2.0 M H2SO4 solution.

Chemistry
2 answers:
noname [10]4 years ago
5 0
 <span>H2SO4 gives 2 moles oh H+ per mole of acid 

[H2SO4] = 2M so [H+] = 4M 

pH = -log(4) = -.6 

Therefore, the pH </span><span>of a 2.0 M H2SO4 solution is -0.6
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
timurjin [86]4 years ago
3 0

Answer:The pH of the solution -0.60 .The pH scales ranges value from 1 to 14.So, the given pH of the solution is coming out to negative which means that in a lab preparation of solution with this pH is not feasible.

Explanation:

The pH of the solution defined as negative logarithm of [H^+] ion concentration.

H_2SO_4(aq)\rightarrow 2H^+(aq)+SO_4^{2-}(aq)

According to reaction 1 moles of sulfuric acid gives 2 moles of H^+

Then 2 mol /L solution of sulfuric acid will give = 4 mol/L of H^+ ions.

pH=-\log[H^+]=-\log[4.0]=-0.60

The pH scales ranges value from 1 to 14.So, the given pH of the solution is coming out to negative which means that in a lab preparation of solution with this pH is not feasible.

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the red line observed in the line spectrum for hydrogen has 3.03x10^-19J, what is the wavelength, in nm, of this?
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Answer:

λ = 6.5604 x 1016 nm

Explanation:

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The energy of the red line in Hydrogen Spectra = 3.03 x 10-19

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In turn

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Solution:

Formula to be Used:

E= hv………………………… (1)

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3.03 x 10-19 J  = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) / λ ……………………….(3)

By rearranging equation 3

λ = (6.626 x 10–34 J s) x (3.00 x 108 m s–1) /3.03 x 10-19  J

λ = 6.5604 x 107 m

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