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IRISSAK [1]
3 years ago
8

A certain company reported selling 5,000 toys during the month of January and expects sales to grow at a rate of 7.5% per month

until the end of that year. How many toys should the company expect to sell by the end of June of that year? 30,158 36,220 43,937 64,500
Mathematics
2 answers:
artcher [175]3 years ago
6 0
The formula is
Fv=p [(1+r)^(t)-1)÷r)
Fv ?
P 5000
R 0.075
T 6. June
Fv=5000 [(1+0.075)^(6)-1)÷0.075]
Fv=36220....answer

Alisiya [41]3 years ago
4 0

Answer:

Step-by-step explanation:

Alright, lets get started.

First month January, the toys are 5000.

In February, toys will be : 5000+\frac{5000*7.5}{100}

In February, toys will be : 5375

In March, toys will be : 5375+\frac{5375*7.5}{100}

In March, toys will be : 5778.125

In April, toys will be : 5778.125+\frac{5778.125*7.5}{100}

In April, toys will be : 6211.484

In May, toys will be : 6211.484+\frac{6211.484*7.5}{100}

In May, toys will be : 6677.345

In June, toys will be : 6677.345+\frac{6677.345*7.5}{100}

In June, toys will be : 7178.146

Hence the total toys will be : 5000+5375+5778.125+6211.484+6677.345+7178.146

Hence the total toys till June will be : 36220   :   Answer

Hope it will help :)

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4 0
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Solve each equation using the quadratic formula. Find the exact solution, then approximate the solution to the nearest hundredth
Anika [276]

Answer:

x_1=\frac{5+\sqrt{33}}{4}≈2.69

x_2=\frac{5-\sqrt{33}}{4}≈-0.19



Step-by-step explanation:

 To solve this problem you  must apply the proccedure shown below:

1. You have that the quadratic formula is:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. To solve the quadratic equation you must substitute the values. So, you have that:

Rewrite the equation:

2x^{2}-5x-1=0

a=2\\b=-5\\c=-1

Then you have:

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3. Therefore, you obtain the following result:

x_1=\frac{5+\sqrt{33}}{4}≈2.69

x_2=\frac{5-\sqrt{33}}{4}≈-0.19


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