97, 19+(11+37)=19+(48)=67 and then add 30 because of 19 and 11 and you get 97
<span>Say the code only needed to be one number long. Going from 0-9, there are ten digits. Therefore, there are ten unique codes.
Now say the code has to be two numbers long. There are ten possibilities
for the first digit, 0-9. But the second digit only has nine
possibilities, since each number has to be different. (The first number
might be 0, so the second can only go from 1-9) For each of the first
ten possibilities, there are nine possibilities for the second. We
multiply those two numbers together, 10 * 9, and we get 90.
Now we just extend the logic. The third number only has eight
possibilities, while the fourth number only has seven. 10 * 9 * 8 * 7 =
5040 possible codes. I hope this helped! has a great day! :)</span>
P(black socks): 24/42 or 12/21
P(black socks without replacing): 23/41. As a result, the probability of randomly picking 2 black socks, without replacement, from the basket is 12/21×23/41=276/861 or 32%. Hope it help!
