OK. I did it, and I have the solution.
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The length of the deck is (5 + 2x) .
The width of the deck is (4 + 2x) .
If the deck didn't have that big hole in the middle where the pool is,
then its area would be
(5 + 2x) · (4 + 2x) .
When you multiply that all out, you get Area = 4x² + 18x + 20
and the question tells us that the area of the whole big rectangle is 90 yds² .
So we can write
4x² + 18x + 20 = 90 .
Subtract 90 from each side: 4x² + 18x - 70 = 0
Divide each side by 2 : 2x² + 9x - 35 = 0
You can use the quadratic equation to solve that and find out that
x = 2.5 yards, and that's what the question is asking you.
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That makes the deck 10 yds high and 9 yds wide.
Total area of the whole big rectangle, (deck + pool ), = 90 yds².
Answer: 187.7 mph
Step-by-step explanation:
v = 125 mph
t = 1.2 min
v2 = ?
t2 = 0.8 min
We can use the rule of 3 here. It's the inverse rule of 3 because as time decreases, speed increases.
![\frac{125mph}{x} =\frac{1.2min}{0.8min}](https://tex.z-dn.net/?f=%5Cfrac%7B125mph%7D%7Bx%7D%20%3D%5Cfrac%7B1.2min%7D%7B0.8min%7D)
![x = \frac{(125)(1.2)}{0.8}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B%28125%29%281.2%29%7D%7B0.8%7D)
![x=187.5mph](https://tex.z-dn.net/?f=x%3D187.5mph)
A=1 and 2
B=2 and 4
C=1,2,7 and 14
D=1,2,4,and 8
Answer:
The boys would have traveled two hours to be at the same point on the trail
Step-by-step explanation:
At the same point on the trail, the two boys would have traveled the same distance.
What this means is that the distance traveled by Neal would be equal to the distance traveled by Abel
Thus, we equate the equation of thur distances.
That would be;
14t = 11t + 6
14t -11t = 6
3t = 6
t = 2 hours
Answer:
it very simple actually, just do it what its saying from any point it wont really matter youll still get it right
Step-by-step explanation: