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Anni [7]
3 years ago
6

Plzzzzz help in all of them ...?.?!!!

Mathematics
1 answer:
Marrrta [24]3 years ago
5 0
2. 44÷4=11. divides evenly, no remainder
3. 39÷3=13 divides evenly, no remainder
4. 32÷5=6 with 2 remainder
5. 57÷8=7 with 1 remainder
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Find the value of f(2) when f(x) = 4x+2
Sloan [31]

Answer:

the answer is 10

Step-by-step explanation:

f(2) that means the value of x= 2

the substitute x=2 in the 4(2)+2.Replace x with 2

6 0
3 years ago
Solve, using linear combination. 5x + y = 2 4x + y = 4
mylen [45]
I hope this helps you

3 0
3 years ago
The rule that maps each domain value to its range value is f(x)= ___x.
kirill115 [55]

Answer:

f(x) = 1/2x

Step-by-step explanation:

When x = -4  the output is -2

We are dividing by 2

When x = -2 the output is -1

f(x) = 1/2 x

Check when x = 2

f(2) = 1/2 (2) =1

3 0
4 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
4 years ago
What is 927 divided by 9
aliya0001 [1]

Answer:103

Step-by-step explanation:

6 0
4 years ago
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