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Georgia [21]
4 years ago
8

Convert 32 degrees F to Celcius and kelvin

Mathematics
1 answer:
aniked [119]4 years ago
3 0

32 degrees F to celcius equals 0

32 degrees F  to Kelvin equals 273.15

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A. 1/5<br><br> B. 1/3<br><br> C. 7/15<br><br> D. 1/2
Allisa [31]

P(B|A)=\dfrac{P(A \cap B)}{P(A)}\\\\ |\Omega|=15\cdot14=210\\ |A|=3\cdot14=42\\ |A \cap B|=3\cdot7=21\\\\ P(A)=\dfrac{42}{210}=\dfrac{7}{35}\\ P(A \cap B)=\dfrac{21}{210}=\dfrac{1}{10}\\\\ P(B|A)=\dfrac{\dfrac{1}{10}}{\dfrac{7}{35}}=\dfrac{1}{10}\cdot\dfrac{35}{7}=\dfrac{1}{2}\Rightarrow \text{D}

4 0
4 years ago
Need help with this math
Ad libitum [116K]

Answer:

Step-by-step explanation:

office at point A =(-7,-5)   ........................in the form (x1,y1)

supermarket and point B = (-2,-6)........in the form (x2,y2)

home Home at point C = (4,-6).............in the from (x3,y3)

find the total distance from A to B + B to C

ABdist= sqrt[ (x2-x1)^2 + (y2-y1)^2 ]

ABdist = sqrt[ (-2-(-7))^2 + (-6-(-5))^2 ]

ABdist = sqrt[ (-2 + 7)^2 + (-6 +5)^2]

ABdist = sqrt[ 5^{2} + (-1)^{2}]

ABdist = sqrt[ 25 + 1 }

ABdist = \sqrt{26}

BCdist= sqrt[ (x3-x2)^2 + (y3-y2)^2 ]

BCdist = sqrt[ (4-(-2))^2 + (-6-(-6))^2]

BCdist = sqrt[ 4+2)^2  + -6+6)^2 ]

BCdist = sqrt [ 6^{2} + 0^{2} ]

BCdist = \sqrt{36}

BCdist = 6

total distance = \sqrt{26} +6

The first answer looks good

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3 years ago
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The second answer choice.
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Answer:

1 3/24

Step-by-step explanation:

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3 years ago
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