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3 years ago

What are the lines of symmetry for this shape?

Mathematics

1 answer:

leva [86]3 years ago

5 0

there would be nun because it not a symmetry shape

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rachel was cutting out some fabric for a friend. she cut a piece that was 5 cm wide and had an area of 20(20)cm. how long was th

Pavlova-9 [17]

Area of a rectangle is L * W

L = x
W = 5

5x = 20 (Divide by 5 on both sides)
x = 4

L=4
W= 5

The length is 4cm

Hope this helps :)

3 0

3 years ago

PJ is Decorating Pupcakes for Rocky´s Birthday Party. Her Color Scheme is Black, Purple, and Green. She Will use This Spinner to

Inga [223]

The answer to your question is C.

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2 years ago

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PLEASE HELP!!!! 13 points!!

IRINA_888 [86]

The answer is A 18 inches

7 0

3 years ago

A student translated the phrase below into an algebraic expression, and then evaluated it for g = one-fourth. Is the student's w

iragen [17]

Answer:

The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third

Step-by-step explanation:

The student was wrong in his evaluation because the correct result should be 1 1/3 (one and one-third) and not 16 and one-third

The expression '1/3 more than the product of four and a number' means

(4g + 1/3)

Evaluating the expression when g = 1/4

You will have

4×1/4 + 1/3

= 1/1 + 1/3

Find the LCM of 1 and 3 and add

= (3+1)/3

=4/3

= 1 1/3

The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third

6 0

3 years ago

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Plant A: A graph has time (weeks) on the x-axis, and height (inches) on the y-axis. A line goes through points (0, 3), (1, 4.8),

butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks, Height

0, 3

1, 4.8

2, 6.6

3, 8.4

The rate of change of height, H per week, t, $\left (\dfrac{dH}{dt} \right )$ for plant A per week is therefore;

$\dfrac{dH}{dt} = \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week$

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks, Height

2, 7.3

3, 8.7

4, 10.1

The rate of change of height, H per week, t, $\left (\dfrac{dH}{dt} \right )$ for plant B per week is given as follows;

$\dfrac{dH}{dt} = \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week$

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

5 0

3 years ago

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