Answer:
it should be 100 I hope this helps
I think that the length's area is 6075
Answer:
Then she needs to save $252.
The median of the data is 6 and the IQR will be 4.
<h3>What are median and IQR?</h3>
The median is the number separating the greater half from the lower half of a sample data in probability theory and statistics. The interquartile range is a measure of statistical dispersion, or the spread of the data, in descriptive statistics.
To calculate the median first arrange the data in the increasing order and then find the mid value.
3,4,6,6,6,8,9,9,12
The middlemost value will be the median.
Median = 6
To calculate the IQR convert the data into lower limits and the upper limits from the median and then calculate the IQR.
3,4,6,6, |6| ,8,9,9,12
Lower Upper
Q1 = (4 + 6)/2 = 5
Q2 = ( 9+9)/2 = 9
IQR = 9 - 5 = 4
Therefore, the median of the data is 6 and the IQR will be 4.
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We have
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A B C D E
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1 yard
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1/5 yard ------------------
7/10 yard
<span>The distance poles B and D= (1-1/5)=4/5 yard
</span>The distance poles B and E= BD+DE=4/5+7/10=(8+7)/10=15/10=3/2 yard
the answer is 3/2 yard (distance poles B and E)
