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vladimir1956 [14]
3 years ago
13

Given that the square root function is only defined for non-negative numbers, define the domain of f in terms of c. {x | ≥ 0}

Mathematics
1 answer:
diamong [38]3 years ago
5 0

Answer:

c:(0;+∞)

Step-by-step explanation:

Given the situation, that the square root function only allows you values above than "0" (not equal neither), then you must consider that every value above 0 belongs to it's domain.

Then, to express the domain, going from your most negative number, to your most possitive number (in this case all positive number, thats why we use infinite)  you must use the parenthesis wich means, you are not considering the value (in this case 0), but the value right after it, to the next value that as we said before, is inifinite. Also remember, that when you express a domain, and use infinite (despite it's going to negative way, or possitive way, it also goes with parenthesis).

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Simora [160]
The answer is -28


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8 0
3 years ago
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86= 10x + 26, what is x?
pashok25 [27]

Answer:

60 = 10x \\ x = 6

6 0
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Is the given value a solution of the inequality​
dsp73

Answer:

35 <5m

35/5 < 5m/5

7 < m

m = 8,9,10,11,12,.......

a + 6 \geq 9

a + 6 - 6 \geq 9 -6

a  \geq 3

a = 3,4,5,6,7,......

8-g > 5

8 -g +g > 5 +g

8 > 5 +g

8 -5 > 5 -5 +g

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Step-by-step explanation:

7 0
2 years ago
Using long division to find the quotient, what changes do you first
lora16 [44]

Answer:

\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4

Step-by-step explanation:

Given

Dividend = 125x^3 - 8

Divisor = 5x - 2

Required

Determine the quotient

See attachment for complete process.

First, divide 125x^3 by 5x

\frac{125x^3}{5x} =25x^2

Write 25x^2 at the top

Multiply 5x - 2 by 25x^2

= 125x^3 - 50x^2

Subtract from 125x^3 - 8

i.e.

125x^3 - 8 - (125x^3 - 50x^2) = 50x^2 - 8

Step 2:

Divide 50x^2 by 5x

\frac{50x^2}{5x} = 10x

Write 10x at the top

Multiply 5x - 2 by 10x

= 50x^2 - 20x

Subtract from 50x^2 - 8

i.e.

50x^2 - 8 - (50x^2 - 20x) = 20x - 8

Step 3:

Divide 20x by 5x

\frac{20x}{5x} = 4

Write 4 at the top

Multiply 5x - 2 by 4

= 20x - 8

Subtract from 20x - 8

i.e.

20x - 8 - (20x - 8) = 0

Hence:

\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4

8 0
3 years ago
Solve the system of equations by substitution. 3/8 x + 1/3 y =17/24 and <br> x + 7y = 8
goblinko [34]
\left \{ {{ \frac{3}{8}x+ \frac{1}{3}y  = \frac{17}{14} } \atop {x+7y=8}} \right.

To solve this system by substitution, first isolate x in the second equation.

x+7y=8
x+7y-7y=8-7y
x=8-7y

Now, plug this expression (8-7y) for x in the top equation to solve for y.

\frac{3}{8} (8-7y)+ \frac{1}{3} y= \frac{17}{14}
3- \frac{21}{8} y+ \frac{1}{3} y= \frac{17}{24}
72-63y+8y=17
72-55y=17
-55y=17-72
-55y=-55
y=1

Now that you have y, plug it into the second equation and solve for x.

x+7y=8
x+7(1)=8
x+7=8
x=1

Last step is to plug your x- and y-values in to both equations to check your work.

\frac{3}{8} (1)+ \frac{1}{3} y= \frac{17}{24}

\frac{3}{8} * \frac{3}{3} = \frac{9}{24} ;  \frac{1}{3} * \frac{8}{8} = \frac{8}{24}

\frac{9}{24} + \frac{8}{24} = \frac{17}{24}  <--True

1+7(1)=8
1+7=8   <--True

Answer:
x=1 \\ y=1
5 0
3 years ago
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