The perimeter of the rectangle is 64
Answer:
C. 0
Step-by-step explanation:
–4j^2 + 3j – 28 = 0
The discriminant is b^2-4ac if >0 we have 2 real solutions
=0 we have 1 real solutions
<0 we have 2 imaginary solutions
a = -4, b =3 c = -28
b^2 -4ac
(3)^2 - 4(-4)*(-28)
9 - 16(28)
9 -448
This will be negative so we have two imaginary solutions.
Therefore we have 0 real solutions
Answer:
10x + 21
Step-by-step explanation:
5x + 2x-9 + 3x + 30 = 10x + 21
A. 30 sixth graders
b. 12 sixth graders
c. If the school has 40 students and the total of students is 70, the number of sixth graders is x
d. 36 students
Answer:
58 degreess
3x+11=4x-5
-3x -3x
11=x-5
+5 +5
16=x
x=6
3(6)+11
18+11
29
29*2
58
Step-by-step explanation:
