Answer:
Figure G.
Step-by-step explanation:
Let's check through the values and calculate the radius and area for all the circle.
For circle R
Diameter = 2 feet
Radius= 1 feet
Area= πr²
Area= 3.14*1
Area= 3.14 feet²
CircleS
Diameter= 4 feet
Radius= 2 feet
Area= πr²
Area= 3.14*2²
Area= 12.56 feet²
Circle T
Diameter= 8 feet
Radius= 4 feet
Area = π r²
area= 3.14*4²
Area=50.24 feet²
Circle U
Diameter= 12 feet
Radius= 6 feet
Area = π r²
area= 3.14*6²
Area=113.04 feet²
The values of the radius and Area all match the graph in figure G
You're really just finding the volume of the cargo-carry part.
V= L x W x H
V= 8.3m x 3m x 4.2m
V= 104.58 m3 or 105 m3 (rounded)
ANSWER: The maximum volume of sand Billy's truck can carry is about 105 m3.
A≈8
V Volume
Using the formula
V=a3
Solving fora
a=V⅓=512⅓≈8
Therefore, to find the lenght of an edge of the cube, just find the cube root of the volume. In this case, the cube root of 512 is equal to 8.
Answer: 
.
Step-by-step explanation:
The given function is
Using chain rule differentiate w.r.t. x.
![\left[\because \dfrac{d}{dx}\sin x=\cos x\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Csin%20x%3D%5Ccos%20x%5Cright%5D)
![f'(x)=\cos(9\ln (x))\left[9\dfrac{d}{dx}(\ln (x))\right]](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Ccos%289%5Cln%20%28x%29%29%5Cleft%5B9%5Cdfrac%7Bd%7D%7Bdx%7D%28%5Cln%20%28x%29%29%5Cright%5D)
![f'(x)=\cos(9\ln (x))\left[9\times \dfrac{1}{x}\right]](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Ccos%289%5Cln%20%28x%29%29%5Cleft%5B9%5Ctimes%20%5Cdfrac%7B1%7D%7Bx%7D%5Cright%5D)
![\left[\because \dfrac{d}{dx}\ln x=\dfrac{1}{x}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Cln%20x%3D%5Cdfrac%7B1%7D%7Bx%7D%5Cright%5D)
Therefore, .
