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m_a_m_a [10]
3 years ago
11

1) Define the three trigonometric ratios (sine, cosine, and tangent) using opposite side, adjacent side, and hypotenuse)​

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
8 0

Answers:

  • sin(angle) = opposite/hypotenuse
  • cos(angle) = adjacent/hypotenuse
  • tan(angle) = opposite/adjacent

These three ratios are often expected to be memorized or written on a flashcard, or reference sheet. I recommend memorizing them as they will come up quite often in trigonometry.

One way to remember is to use phrase "SOH CAH TOA" which could sound like "soak a toe-a" when you pronounce it out.

SOH = sine opposite hypotenuse

CAH = cosine adjacent hypotenuse

TOA = tangent opposite adjacent

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. Here is an equation 2x + 9 = -15. Write three different equations that have the same solution as 2x + 9 = -15. Show or explain
Anettt [7]

Answer:

1. x-3=-15
2.2x=-24
3.2x-3=-27

Step-by-step explanation:

Given the following question:

2x+9=-15

To find three equations that have the same solution as the given equation we have to first solve the equation.

2x+9=-15
9-9=0
-15-9=-24
2x=-24
2x\div2=x
-24\div2=-12
x=-12

<u>Equation one:</u>
x-3=-15
-3+3=0
-15+3=-12
x=-12

<u>Equation two:
</u>2x=-24
2x\div2=x
-24\div2=-12
x=-12

<u>Equation three:</u>
2x-3=-27
-3+3=0
-27+3=-24
-24\div2=-12
x=-12

Hope this helps.

4 0
2 years ago
The potential energy, P, in a spring is represented using the formula P = kx2. Lupe uses an equivalent equation, which is solved
ella [17]

Original equation is P=kx^{2}

So, kx^{2} =P and

k=\frac{P}{x^{2} }

If we compare this equation with the given options, we can easily find that this matches with the last one k=\frac{p}{2x^{2} } with P = p/2.

Hence, correct option is k=\frac{p}{2x^{2} }.

4 0
3 years ago
Read 2 more answers
Solve for a<br><br> 5 + 7a = 19
Bess [88]
A = 2 all you gotta do is 7 x 2 which is 14 and add 5 to it which equals 19
8 0
3 years ago
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Express the radical using the imaginary unit i
valentinak56 [21]

Answer:

=\pm i\sqrt{66}

Step-by-step explanation:

So we have:

\pm\sqrt{-66}

This is the same as:

=\pm\sqrt{66\cdot-1}

Separate:

=\pm\sqrt{66}\cdot\sqrt{-1}

Replace the second term with i:

=\pm i\sqrt{66}

The square root of 66 cannot be simplified.

So, this is our answer :)

7 0
3 years ago
Help please help me!!!!!!
Lera25 [3.4K]

Answer:

441

Step-by-step explanation:

hope this worknnnwnennenenb something s s s. sbenennene ene e. e e ene enneenjejej

7 0
2 years ago
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