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Nostrana [21]
3 years ago
10

A system of equations is given below:

Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0
To solve by substitution:

2x + 7 (4x-3) = 41
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Five times the sum of a number and six is equal to three times the difference of a number and ten.
romanna [79]

Answer: 6x + 6

Step-by-step explanation:x = the number 5x + (x + 6) {five times the number added to the sum of the number and six} = 5x + x + 6 {took out parentheses}

6 0
3 years ago
All questions to be solved using linear combination.
monitta
1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)
8 0
3 years ago
Hey guys please solve this basic equation for me <br> 5 + 2x &lt; 9
nikitadnepr [17]

Answer:

x < 2

Step-by-step explanation:

Given

5 + 2x < 9 ( subtract 5 from both sides )

2x < 4 ( divide both sides by 2 )

x < 2

6 0
3 years ago
The following data points represent the number of hours each of the staff members at Daniel's Department Store slept on Thanksgi
Slav-nsk [51]

Sort the data into this order:

2.6, 3, 4.9, 5, 5, 6, 6, 7.9, 8, 8.2

^

there are 10 data points in total, therefore the Interquartile Range = between the 5th and the 6th numbers, which are 5 and 6

(5+6)/2= 5.5

5 0
4 years ago
If you know the answer your a genius at math^
nirvana33 [79]

Answer: I think its B

Step-by-step explanation: hoped this helped :)

4 0
3 years ago
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