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ZanzabumX [31]
3 years ago
7

joey's mom baked two dozen cookies . that night, there were only 14 cookies left. what percentage of the cookies were eaten?

Mathematics
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

41.67 % ( to 2 dec. places )

Step-by-step explanation:

Since 2 dozen cookies were baked, that is 24 and 14 were left.

Then 10 were eaten.

Calculate the percentage eaten as

percentage = \frac{numbereaten}{original} × 100%

percentage eaten = \frac{10}{24} × 100% ≈41.67%

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Step-by-step explanation:

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It’s not C so I don’t which is the correct answer so can someone plz help me with this plzzz
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Step-by-step explanation:

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HURRY ASAP PLZZZZ ANYONE???? There are 25 towns in a certain country, and every pair of them is connected by a train route. How
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Answer:

25 train routes

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
For the composite function, identify an inside function and an outside function and write the derivative with respect to x of th
alexira [117]

Answer:

The inner function is h(x)=4x^2 + 8 and the outer function is g(x)=3x^5.

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

Step-by-step explanation:

A composite function can be written as g(h(x)), where h and g are basic functions.

For the function f(x)=3(4x^2+8)^5.

The inner function is the part we evaluate first. Frequently, we can identify the correct expression because it will appear within a grouping symbol one or more times in our composed function.

Here, we have 4x^2+8 inside parentheses. So h(x)=4x^2 + 8 is the inner function and the outer function is g(x)=3x^5.

The chain rule says:

\frac{d}{dx}[f(g(x))]=f'(g(x))g'(x)

It tells us how to differentiate composite functions.

The function f(x)=3(4x^2+8)^5 is the composition, g(h(x)), of

     outside function: g(x)=3x^5

     inside function: h(x)=4x^2 + 8

The derivative of this is computed as

\frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=3\frac{d}{dx}\left(\left(4x^2+8\right)^5\right)\\\\\mathrm{Apply\:the\:chain\:rule}:\quad \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx}\\f=u^5,\:\:u=\left(4x^2+8\right)\\\\3\frac{d}{du}\left(u^5\right)\frac{d}{dx}\left(4x^2+8\right)\\\\3\cdot \:5\left(4x^2+8\right)^4\cdot \:8x\\\\120x\left(4x^2+8\right)^4

The derivative of the function is \frac{d}{dx}\left(3\left(4x^2+8\right)^5\right)=120x\left(4x^2+8\right)^4.

3 0
3 years ago
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