Question

A rocket is launched from atop a 36-foot cliff with an initial velocity of 107 feet per second. the height of the rocket, t seconds after launch is given by the equation . use the quadratic formula to find out how long after the rocket is launched it will hit the ground (h = 0). round your answer to the nearest tenth of a second.
a. 1.5 sec

b. 0.3 sec

c. 7.0 sec

d. 6.3 sec

Answer 1

Answer:

Time taken, t = 7 seconds  

Step-by-step explanation:

It is given that,

A rocket is launched from atop a 36-foot cliff with an initial velocity of 107 feet per second. When an object is project from certain height, then the height of the object is given by the following function as :

$h(t)=-16t^2+vt+h$................(1)

Where, h = initial height = 36 foot

v is initial velocity, v = 107 feet per second

We have to find how long after the rocket is launched it will hit the ground (h = 0)

Using above parameter in equation (1)

$-16^2+107t+36=0$

On solving the above quadratic equation, we get the value of t = 7 seconds

Hence, the correct option is (c) " 7 sec ".

Answer 2

I just got this one correct, it's C. 7.0 :) Hope i helped!