All categories

3 years ago

20/14 as a proportional ratio

Mathematics

1 answer:

ra1l [238]3 years ago

8 0

Answer:

Search it up

Step-by-step explanation:

Step by step: go to google, search up your question bam

You might be interested in

Eight values have a mean of 7. a ninth value is added. the new mean is 9. what is the new value

My name is Ann [436]

Answer:

25 because the 8 values must times with 7 and will get 56. when the ninth value added , let the ninth value as y , 56+y , the new mean is 9 . so it will be like this , 56+y over 9 times with 9

4 0

3 years ago

Find the formula for the area A and the perimeter P of the shape shown find the area and perimeter when R is 5 cm find R when A

Ghella [55]

Answer:

1)Area; A = ¼πr²

Perimeter; P = πr/2 + 2r

2)A = 19.63 cm²

P = 17.85 cm

3) r = 8.885 cm

4) r = 14 cm

Step-by-step explanation:

This is a quadrant of a circle. Thus;

Area of a circle is πr². A quadrant is a quarter of a circle. Thus;

Formula for Quadrant Area is; A = ¼πr²

A) Perimeter of a circle is 2πr. Thus, perimeter of a quadrant is a quarter of the full circle perimeter.

Formula for the quadrant perimeter in the image given is;

P = 2πr/4 + 2r

P = πr/2 + 2r

B) When r is 5 cm;

A = ¼π(5)²

A = 19.63 cm²

P = π(5)/2 + 2(5)

P = 17.85 cm

C) when A is 100cm²:

¼πr² = 100

r² = 100 × 4/π

r² = 78.9358

r = √78.9358

r = 8.885 cm

D) when P = 50 cm.

50 = πr/2 + 2r

50 = (½π + 2)r

r = 50/(½π + 2)

r = 14 cm

6 0

3 years ago

Q4.

goblinko [34]

The coding of the statistic is used to make it easier to work with the large sunshine data set

The mean of the sunshine is 3.05 $\overline 6$

The standard deviation is approximately 18.184

Reason:

The given parameters are;

The sample size, n = 3.

∑x = 947

Sample corrected sum of squares, Sₓₓ = 33,065.37

The mean and standard deviation = Required

Solution:

$Mean, \ \overline x = \dfrac{\sum x_i}{n}$

The mean of the daily total sunshine is therefore;

$Mean, \ \overline x = \dfrac{947}{30} \approx 31.5 \overline 6$

$s = \dfrac{x}{10 } - \dfrac{1}{10}$

$E(s) = \dfrac{Ex}{10 } - \dfrac{1}{10}$

$E(s) = \dfrac{31.5 \overline 6}{10 } - \dfrac{1}{10} = 3.05 \overline 6$

The mean ≈ 3.05 $\overline 6$

Alternatively

, $The \ mean \ of \ the \ daily \ total \ sunshine, \, s = \dfrac{31.5 \overline 6 - 1}{10 } = 3.05\overline 6$

The mean of the daily total sunshine, $\overline s$ ≈3.05 $\overline 6$

$Var(s) = Var \left(\dfrac{x}{10 } - \dfrac{1}{10} \right)$

$Var(s) = \left(\dfrac{1}{10}\right)^2 \times Var \left(x \right)$

Therefore;

$Var(s) = \left(\dfrac{1}{10}\right)^2 \times 33,065.37 = 330,6537$

Therefore;

$s = \sqrt{330.6537} \approx 18.184$

The standard deviation, $s_s$ ≈ 18.184

Learn more about coding of statistic data here:

brainly.com/question/14837870

3 0

2 years ago

The Director of Admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall sem

VMariaS [17]

Answer:

Variance = 24900

Standard Deviation = 157.7973

Step-by-step explanation:

We are given the following in the question:

Number of admissions: 1000 1200 1500

Admissions Probability: 0.6 0.3 0.1

Formula:

$E(x) = \displaystyle\sum x_iP(x_i)\\E(x) = 1000(0.6) + 1200(0.3) + 1500(0.1)\\E(x) = 1110\\E(x^2) = \displaystyle\sum x_i^2P(x_i)\\E(x^2) = (1000)^2(0.6) + (1200)^2(0.3) + (1500)^2(0.1)\\E(x^2) = 1257000$