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3 years ago

Please answer i will give you braineiest!!! answer 1 2 and 3 i will give you extra 40 points!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

Rama09 [41]3 years ago

3 0

Answer:

Some ages that Mark could possibly be are...

16, 17, 18, 19, and 20. I found my answers because to have a job or work at a program, you have to be at least 16. So Mark could be 16, 17, 18, 19, or 20. He would be able to work being 21 because that is the drinking age and you are already in the adult stage and you are old enough to be responsible with what you do.

Step-by-step explanation:

<h2>Hope this helps and have a great day :)</h2>

You might be interested in

If these two figures are similar what is the measure of the missing side length J?

Ray Of Light [21]

If the long side on both is 9ft and 3ft then 3•3 is 9 so for the short side you do the same. If the short side is 1ft and the other is "j" then it's 1•3 is 3.

1•3=3
Sorry if it's confusing the way I explained it.

3 0

3 years ago

Prove A-(BnC) = (A-B)U(A-C), explain with an example

NikAS [45]

Answer:

Prove set equality by showing that for any element $x$ , $x \in (A \backslash (B \cap C))$ if and only if $x \in ((A \backslash B) \cup (A \backslash C))$ .

Example:

$A = \lbrace 0,\, 1,\, 2,\, 3 \rbrace$ .

$B = \lbrace0,\, 1 \rbrace$ .

$C = \lbrace0,\, 2 \rbrace$ .

$\begin{aligned} & A \backslash (B \cap C) \\ =\; & \lbrace 0,\, 1,\, 2,\, 3 \rbrace \backslash \lbrace 0 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace \end{aligned}$ .

$\begin{aligned}& (A \backslash B) \cup (A \backslash C) \\ =\; & \lbrace 2,\, 3\rbrace \cup \lbrace 1,\, 3 \rbrace \\ =\; & \lbrace 1,\, 2,\, 3 \rbrace\end{aligned}$ .

Step-by-step explanation:

Proof for $[x \in (A \backslash (B \cap C))] \implies [x \in ((A \backslash B) \cup (A \backslash C))]$ for any element $x$ :

Assume that $x \in (A \backslash (B \cap C))$ . Thus, $x \in A$ and $x \not \in (B \cap C)$ .

Since $x \not \in (B \cap C)$ , either $x \not \in B$ or $x \not \in C$ (or both.)

If $x \not \in B$ , then combined with $x \in A$ , $x \in (A \backslash B)$ .
Similarly, if $x \not \in C$ , then combined with $x \in A$ , $x \in (A \backslash C)$ .

Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ as required.

Proof for $[x \in ((A \backslash B) \cup (A \backslash C))] \implies [x \in (A \backslash (B \cap C))]$ :

Assume that $x \in ((A \backslash B) \cup (A \backslash C))$ . Thus, either $x \in (A \backslash B)$ or $x \in (A \backslash C)$ (or both.)

If $x \in (A \backslash B)$ , then $x \in A$ and $x \not \in B$ . Notice that $(x \not \in B) \implies (x \not \in (B \cap C))$ since the contrapositive of that statement, $(x \in (B \cap C)) \implies (x \in B)$ , is true. Therefore, $x \not \in (B \cap C)$ and thus $x \in A \backslash (B \cap C)$ .
Otherwise, if $x \in A \backslash C$ , then $x \in A$ and $x \not \in C$ . Similarly, $x \not \in C \!$ implies $x \not \in (B \cap C)$ . Therefore, $x \in A \backslash (B \cap C)$ .

Either way, $x \in A \backslash (B \cap C)$ .

Therefore, $x \in ((A \backslash B) \cup (A \backslash C))$ implies $x \in A \backslash (B \cap C)$ , as required.

8 0

3 years ago

What is 444/88/145/140

disa [49]

First of all, I suppose that you are dividing, /.
Since, you don't have any other symbols here, i.e. + -*.
you work from left to right
444/88 is exactly 5.04545454545
5.04545454545/145 is exactly 0.03479623824
0.03479623824/140 is exactly 0.00024854455

so the answer to this is 0.00024854455

Hope this helps in some way ;)

7 0

4 years ago

-6x - 24 = 10 -2x - 2 Please help & show you get to the answer

Zanzabum

Solve for x by simplifying both sides of the equation, the isolating the variable. x=-8

3 0

3 years ago

Read 2 more answers

Which is the graph of the following inequality?

icang [17]

Answer:

D) graph D