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4 years ago

14

A pyramid has a volume of 1,944 inch^3 and a rectangular base with the dimensions 18 inches by 9 inches. What is the height of t

he pyramid?
4 in.
12 in.
24 in.
36 in.

1 answer:

Scrat [10]4 years ago

4 0

The answer is 36 in

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Anybody got snap i need help turning in my missing work

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3 years ago

A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po

Mariana [72]

Answer:

The work done to pump all of the kerosene from the tank to an outlet is $W=45238.9\: J$

Step-by-step explanation:

The work is defined by:

$W=\int dFdx$ (1)

The force here will be the product between the volume and the kerosene weighing, so we have :

$dF=\pi R^{2}dy*50$

This force will be in-lbs.

Where R is the radius (3 feet)

Then using (1), we have:

$W=\int \pi R^{2}dy*50(8-y)$

Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.

$W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)$

$W=450\pi \int_{0}^{8}dy(8-y)$

$W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)$

$W=450\pi(8y|_{0}^{8} -\frac{y^{2}}{2}|_{0}^{8})$

$W=450\pi(8*8 -\frac{8^{2}}{2})$

$W=450\pi(64 -\frac{64}{2})$

Therefore, the work done to pump all of the kerosene from the tank to an outlet is $W=45238.9\: J$

I hope it helps you!

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3 years ago

GIven that GR= x+5 and GP= 2x-3 which expression below calculates the perimeter of this gate? (x+5) + (2x-3) (x+5) + (2x-3) 2(x+

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Answer:

P = 2(x + 5) + 2(2x - 3)

Step-by-step explanation:

GIven that GR= x+5 and GP= 2x-3 which expression below calculates the perimeter of this gate?

The shape of the gate is rectangular.

Hence, the Perimeter of a rectangle (the gate) = 2L + 2W

Where :

L = GR = x + 5

W = GP = 2x - 3

Hence,the perimeter of the gate is

P = 2(x + 5) + 2(2x - 3)

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3 years ago

If y has moment-generating function m(t) = e 6(e t −1) , what is p(|y − µ| ≤ 2σ)?

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Since $\mathrm M_Y(t)=e^{6(e^t-1}$ , we know that $Y$ follows a Poisson distribution with parameter $\lambda=6$ .

Now assuming $\mu,\sigma$ denote the mean and standard deviation of $Y$ , respectively, then we know right away that $\mu=6$ and $\sigma=\sqrt6$ .

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