Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/<span>∆x
Crossing the 1s , the 2xs, and the x^2s out, we get
(2x</span>∆x+∆x^2-2∆x)/<span>∆x
Dividing the </span><span>∆x, we get
2x+</span><span>∆x-2.
Making the limit of </span><span>∆x=0, we get 2x-2.</span>
Answer:
-2r-19p
Step-by-step explanation:
-4p-2r-15p
add like terms
-2r-19p
Answer:
7c + 5
Step-by-step explanation:
(8c+8)–(c+3)
8c - c = 7c
8 - + 3 = 5
7c + 5